Answer : The initial rate of the reaction is, 
Explanation :
First we have to calculate the rate constant of the reaction.
Expression for rate law for first order kinetics is given by :
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken for the process = 44 s
= initial amount or concentration of the reactant = 0.1108 M
= amount or concentration left time 44 s = 0.0554 M
Now put all the given values in above equation, we get:


Now we have to calculate the initial rate of the reaction.
Initial rate = K [A]
At t = 0, ![[A]=[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D)
Initial rate = 0.0157 × 0.1108 = 
Therefore, the initial rate of the reaction is, 
Is the water line of boat when someone boards or leaves it.
The correct answer is A; or 9.38x10^-3.
Explanation:
f=3.20x10^10 c= 3.00x10^8
Once you divide those by each other, your answer is 9.83x10^-3
Hope this helps!! :)