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3 years ago

The distance between the points is. 3.16227766016838

Chemistry

1 answer:

OLEGan [10]3 years ago

6 0

Answer:

if u have to round it to the nearest ones plat 3.2 or 3.1 and if u have to round to the tenths place 3.16

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Name the functional group in the following molecule: H-C(Triple Bond)C-CH2CH3

Dima020 [189]

Here is your answer

Since, carbon atoms are triple bonded.

So functional group present in the compound is ALKYNE

HOPE IT IS USEFUL

3 0

3 years ago

calculate the enthalpy change for converting 1.00 mol of liquid water at 100 C to water vapor at 145 degree celsius for water Δ

Svetllana [295]

Answer:

q1 = mCpΔT

= 18.016g × 1.84J/g.K × (418.15-373.15)

= 1491.72 J

q2 = n×ΔH vap

= 1mol ×44.0kJ/mol

= 44KJ

∴ qtotal = q1+ q2

= 1.498kJ + 44.0kJ

= 45.498KJ

Explanation: The heat flow can be separated into steps.all that is being observed at a constant pressure,the heat flow is equal to the enthalpy.

8 0

3 years ago

Engine size is measured by how much air the cylinders displace. A 1996 Pontiac V8 has an engine size of 316.6 cubic inches. What

inna [77]

The size of this engine in cubic meters is $0.0052 m^{3}$ .

Explanation:

As it is stated that engine size can be measured depending upon the amount of air the cylinders displace, it is also stated that the engine of model Pontiac V8 has a size of 316.6 cubic inches. The problem is to convert the size of engine in cubic meters. We know that 1 inch = 0.0254 m.

Then $1 inch^{3}=(0.0254)^{3} m^{3}$

As here the size of engine is 316.6 cubic inches, then in metres it will be

$316.6 \text { inches }^{3}=316.6 \times(0.0254)^{3} \mathrm{m}^{3}=0.0052 \mathrm{m}^{3}$

Thus, the size of the engine in cubic meters will be $0.0052 m^{3}$ .

3 0

3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

How many moles of solute are in 53.1 mL of 12.5M HCI?

Deffense [45]

Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).

6 0

3 years ago