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Nataly_w [17]
3 years ago
10

Solve for X please: -ax+4b>9

Mathematics
2 answers:
Orlov [11]3 years ago
7 0
Lets solve for X
(-a)(x)+4b>9
---------------------------------------------------------
Step one: Add -4b to both sides
---------------------------------------------------------
-ax+4b+-4b>9+-4b
-ax>-4b+9
--------------------------------------------------------
Step 2: divide both d=sides by -a
--------------------------------------------------------
-ax/-a > -4b+9/-a
-------------------------------------------------------
ANSWER: x < 4b-9/a
------------------------------------------------------
Ulleksa [173]3 years ago
4 0
So what you do is subtract 4b on both sides so it will be -ax=9+4b then divide x on both sides and you have your answer 

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It is impossible because it's base is not circular. A solid of revolution is <span>obtained by rotating a </span>plane curve<span> around some </span>straight line, that is, <span>the </span>axis of revolution that lies on the same plane. The closest to a square pyramid applying this concept is by rotating a right triangle around the opposite or adjacent side (the axis), but the shape that you get is a straight circular cone. 
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3 years ago
Find the domain of the function shown. Write the answer in interval notation.
lara31 [8.8K]

( - ∞, 3) ∪ (3, ∞ )

The domain is the set of values of x which make f(x) defined

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve x - 3 = 0 ⇒ x = 3

domain : (- ∞, 3) ∪ (3, ∞ )


7 0
4 years ago
(1 point) A pond contains 100 fish, of which 40 are carp. If 20 fish are caught from the lake, what are the mean and variance of
marta [7]

Answer:

E(X) = 6

Var(X) = 3.394

Step-by-step explanation:

Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each

of the (100, 20) ways to catch the 20 fishes will be equally likely.

Thus, we can say that X fulfills a hypergeometric

distribution with parameters as follows;

n = 20, N = 100, k = 30

Formula for expected mean value in hypergeometric distribution is;

E(X) = nk/N

E(X) = (20 × 30)/100

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Formula for variance is;

Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]

Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]

Var(X) = 6 × 0.5657

Var(X) = 3.394

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3 years ago
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Answer:

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3 years ago
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