2 years ago

X³=343-¹ find the positive value of x that makes the equation true

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

8 0

$x^3=343^{-1}\\\\x^3=(7^3)^{-1}\\\\x^3=7^{-3}\\\\x^3=\left(\frac{1}{7}\right)^3\iff\boxed{x=\frac{1}{7}}$

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The amount in kilograms, a, of a radioactive element that remains after t hours can be modeled by the equation a= 0.65(0.92)to t

elena-14-01-66 [18.8K]

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The rate of decrease is 8%

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we know that

The general equation for the radioactive decay can be written as:

$a=a_0(1-r)^t$

where

a is the amount in kilograms after time t.

a_0 is the original amount of the substance or y-intercept of the function

r is the decay rate, written in decimals.

t is the time

In this problem we have

$a=0.65(0.92)^t$

$a_0=0.65\\(1-r)=0.92$

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Convert to percentage

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