4q-2r/3m=7 solve for q
1 answer:
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9514 1404 393
Answer:
3.61 seconds
Step-by-step explanation:
The bird starts 50 feet in the air, so will come down to a height of 40 feet after 3.61 seconds.
We want to solve h = 40.
40 = -16t^2 +55t +50
16t^2 -55t -10 = 0
t = (55 +√(55^2 -4(16)(-10)))/(2(16)) = (55 + √3665)/32 ≈ 3.61060
The bird will be 40 ft above the ground the first time after about 3.61 seconds.
The graph of g is one-fifth as steep as the graph of f.
The function g basically takes the inputs for f and multiplies them by one-fifth, which means the outputs are one-fifth times those of f. Multiplying by one-fifth makes something smaller (it's the same as dividing by five). It helps to visualize this relationship, so I've attache the graphs below.
The function g basically takes the inputs for f and multiplies them by one-fifth, which means the outputs are one-fifth times those of f. Multiplying by one-fifth makes something smaller (it's the same as dividing by five). It helps to visualize this relationship, so I've attache the graphs below.
Let's look at an example:
2.24 x 21.6
Do normal multiplication and get
48384 This is not correct, until we put the decimals in. To know how to do this, count the number of decimal spaces from the factors. In 2.24, there are 2, because .24. In 21.6 there are 1 because of .6. This mean three places, so 48384 becomes
48.384
~theLocoCoco