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insens350 [35]
3 years ago
13

For a steel alloy it has been determined that a carburizing heat treatment of 14 h duration at 809°C will raise the carbon conce

ntration to 0.54 wt% at a point 3.6 mm from the surface. Estimate the time necessary to achieve the same concentration at a 6.0 mm position for an identical steel and at a carburizing temperature of 1100°C. Assume that D0 is 2.5 × 10-5 m2/s and Qd is 120 kJ/mol.
Engineering
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

t_2 = 27.7 hr

Explanation:

Given data:

carbon concentration  =  0.54%

from the relation given below calculate the time required to achieve concentration at 6.00 mm from surface

\frac{x^2}{Dt} = constant

D considered constant

\frac{x^2}{t} =  constant

here, x POSITION FROM SURFACE, t is time required to achieve concentration

\frac{x_1^2}{t_1} = \frac{x_2^2}{t_2}

\frac{3.6^2}{14} = \frac{6^2}{t_2}

t_2 = 27.7 hr

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Answer:

Explanation:

Given

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750\pi =\frac{0.002t^3}{3}+4t

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on solving we get t=139.23\ s

Thus velocity at t=139.23\ s

v=42.76\ s

(b)Acceleration when car has traveled three-fourth the way of track

normal acceleration a_n=\frac{v^2}{r}=\frac{(42.76)^2}{500}

a_n=3.658\ m/s^2

Tangential acceleration a_t at t=139.23\ s

a_t=0.556\ m/s^2

Net acceleration a_t=\sqrt{(a_n)^2+(a_t)^2}

a_n=\sqrt{(3.658)^2+(0.556)^2}

a_n=3.7\ m/s^2

   

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At a point on the free surface of a stressed body, the normal stresses are 20 ksi (T) on a vertical plane and 30 ksi (C) on a ho
victus00 [196]

Answer:

The principal stresses are σp1 = 27 ksi, σp2 = -37 ksi and the shear stress is zero

Explanation:

The expression for the maximum shear stress is given:

\tau _{M} =\sqrt{(\frac{\sigma _{x}^{2}-\sigma _{y}^{2}  }{2})^{2}+\tau _{xy}^{2}    }

Where

σx = stress in vertical plane = 20 ksi

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Replacing:

32=\sqrt{(\frac{20-(-30)}{2} )^{2} +\tau _{xy}^{2}  }

Solving for τxy:

τxy = ±19.98 ksi

The principal stress is:

\sigma _{x}+\sigma _{y} =\sigma _{p1}+\sigma _{p2}

Where

σp1 = 20 ksi

σp2 = -30 ksi

\sigma _{p1}  +\sigma _{p2}=-10 ksi (equation 1)

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