Answer:
Explanation:
Given
velocity at A is 
For 
velocity is increasing at 
Tangential acceleration is given by





at 


thus 
Velocity in terms of Displacement is given by



When car has traveled
th of distance i.e.




on solving we get 
Thus velocity at 

(b)Acceleration when car has traveled three-fourth the way of track
normal acceleration 

Tangential acceleration 

Net acceleration 

Answer:
The principal stresses are σp1 = 27 ksi, σp2 = -37 ksi and the shear stress is zero
Explanation:
The expression for the maximum shear stress is given:

Where
σx = stress in vertical plane = 20 ksi
σy = stress in horizontal plane = -30 ksi
τM = 32 ksi
Replacing:

Solving for τxy:
τxy = ±19.98 ksi
The principal stress is:

Where
σp1 = 20 ksi
σp2 = -30 ksi
(equation 1)
equation 2
Solving both equations:
σp1 = 27 ksi
σp2 = -37 ksi
The shear stress on the vertical plane is zero