Answer & Explanation:
"The force <em>on a cutting tool</em> are 2600N vertically downward" sounds a little unusual, since most of the time, the tool is above the object to be cut in such a way that the force acting "ON the tool" is upwards. We will accept the statement as it is (downwards).
Since the two forces are acting at right angles to each other, the resultant can be found using Pythagoras theorem, namely
resultant = sqrt(2600^2+2100^2) = 3342 N (approx.)
The angle can be found using the arcTangent function, or
angle = arcTangent(2600/2100) = 51.07 degrees below the horizontal, since the 2600 N force is acting downwards.
Answer:
C=76 in (answer in inches to the nearest inch)
Explanation:
The statement of question tells us only 2.5% players to be taller than the cut off height C. It means 97.5% are smaller than the cut off height C. We first have to look in standardized normal distribution tables to find the corresponding value of 97.5% which is 1.96.
Now:
z=1.96
mean=μ=70.6
Standard deviation=σ=2.8
Formula:
C=(1.96*2.8)+70.6
C=76.088 in
C=76 in (answer in inches to the nearest inch)
Answer:
C₁₀ = 6.3 KN
Explanation:
The catalog rating of a bearing can be found by using the following formula:
C₁₀ = F [Ln/L₀n₀]^1/3
where,
C₁₀ = Catalog Rating = ?
F = Design Load = 2.75 KN
L = Design Life = 1800 rev/min
n = No. of Hours Desired = 10000 h
L₀ = Rating Life = 500 rev/min
n₀ = No. of Hours Rated = 3000 h
Therefore,
C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3
C₁₀ = (2.75 KN)(2.289)
<u>C₁₀ = 6.3 KN</u>
Answer:
Explanation:
Hence;
The 4-to-1 MUX and inverter is shown in the attached file below.