Thank u very much , im doin good wby :)
Answer:
V = 0.00459 ft/s
Explanation:
Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f with τ and from that derive the equation for V.
Fѵf = τ . A
Where τ = µ. du/dy = µ . V/b , and A = π . D . l from this Follows:
Fѵf= (V. A .µ )/b V= ( Fѵf .b )/(A.µ)
Placing all the known values in the equation ( remember to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :
ft2
V = ((0.5lb) . (0.002/12 ft))/(π . (5.48/12 ft) . (9.50/12 ft) . (0.016 lb.s/(ft^2 )))
V = 0.00459 ft/s
Answer:
B
Explanation:
The only way the 15mph would fit
Answer:
0.0432 m^3/s
Explanation:
Internal diameter of smaller pipes = 2.5 cm = 0.025 m
pipa wall thickness = 3 mm = 0.003 m
internal diameter of larger pipes = 8 cm = 0.8 m
velocity of region between smaller and larger pipe = 10 m/s
Calculate discharge in m^3/s
First we calculate the area of the smaller pipe
A = 
= 
= 0.00023571 m^2
next we calculate area of fluid between the smaller pipes and larger pipe
A = ![[\frac{\pi }{4} D^{2} _{L} ] - 3(A_{s})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20D%5E%7B2%7D%20_%7BL%7D%20%20%5D%20-%203%28A_%7Bs%7D%29)
= ![[ \frac{\pi }{4} (0.08 )^2 - 3 ( 0.00023571 )]](https://tex.z-dn.net/?f=%5B%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%280.08%20%29%5E2%20-%203%20%28%200.00023571%20%29%5D)
= [ 0.00502857 - 0.00070713 ]
= 0.00432144 m^2
hence the discharge in m^3/s
Q = AV
= 0.00432144 * 10
= 0.0432 m^3/s
