- The conversion of 47,000 Ohms to kilo-ohms is equal to 47 kilo-ohms.
- The conversion of 47,000 Ohms to mega-ohms is equal to 0.047 kilo-ohms.
<h3>What is
resistance?</h3>
Resistance can be defined as an opposition to the flow of current in an electric circuit. Also, the standard unit of measurement of the resistance of an electric component is Ohms, which can be converted to kilo-ohms or mega-ohms.
For Ohms to kilo-ohms, we have:
1 Ohms = 0.001 kilo-ohms
47,000 Ohms = X kilo-ohms
Cross-multiplying, we have:
X = 0.001 × 47000
X = 47 kilo-ohms.
For Ohms to mega-ohms, we have:
1,000,000 ohms = 1 mega-ohms
47,000 Ohms = X mega-ohms
Cross-multiplying, we have:
X1,000,000 = 47,000
X = 47,000/1,000,000
X = 0.047 kilo-ohms.
Read more resistance here: brainly.com/question/19582164
#SPJ1
Answer:
A. Yes
B. Yes
Explanation:
We want to evaluate the validity of the given assertions.
1. The first statement is true
The sine rule stipulates that the ratio of a side and the sine of the angle facing the side is a constant for all sides of the triangle.
Hence, to use it, it’s either we have two sides and an angle and we are tasked with calculating the value of the non given side
Or
We have two angles and a side and we want to calculate the value of the side provided we have the angle facing this side in question.
For notation purposes;
We can express the it for a triangle having three sides a, b, c and angles A,B, C with each lower case letter being the side that faces its corresponding big letter angles
a/Sin A = b/Sin B = c/Sin C
2. The cosine rule looks like the Pythagoras’s theorem in notation but has a subtraction extension that multiplies two times the product of the other two sides and the cosine of the angle facing the side we want to calculate
So let’s say we want to calculate the side a in a triangle of sides a, b , c and we have the angle facing the side A
That would be;
a^2 = b^2 + c^2 -2bcCosA
So yes, the cosine rule can be used for the scenario above
Answer: The complete part of the question is to find the exit velocity
Explanation:
Given the following parameters
Inlet pressure = 700kpa
outlet pressure = 40kpa
Temperature = 80°C = 353k
mass flow rate = 1 kg/s
The application of the continuity and the bernoulli's equation is employed to solve the problem.
The detailed steps and the appropriate formula is as shown in the attached file.
Answer:
See attached pictures.
Explanation:
See attached pictures for detailed explanation.
