Just doing a experiment.......................... for 21 points
2 answers:
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Answer:
attached below
Explanation:
Answer:
The original length of the specimen
Explanation:
Original diameter = 30 mm
Final diameter = 30.04 mm
Change in diameter Δd = 0.04 mm
Final length = 105.20 mm
Elastic modulus E = 65.5 G pa = 65.5 × M pa
Shear modulus G = 25.4 G pa = 25.4 × M pa
We know that the relation between the shear modulus & elastic modulus is given by
This is the value of possion's ratio.
We know that the possion's ratio is given by
0.00476
Final length = 105.2 m
Original length
This is the original length of the specimen.
Answer:
a) 764.45K
b) 210.48 kJ/kg
c) 30.14%
Explanation:
pressure ratio = 10
minimum temperature = 295 k
maximum temperature = 1240 k
isentropic efficiency for compressor = 83%
Isentropic efficiency for turbine = 87%
<u>a) Air temperature at turbine exit </u>
we can achieve this by interpolating for enthalpy
h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17 for Ideal gas properties of air
T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) = 764.45K
<u>b) The net work output </u>
first we determine the actual work input to compressor
Wc = h2 - h1 ( calculated values )
= 626.57 - 295.17 = 331.4 kJ/kg
next determine the actual work done by Turbine
Wt = h3 - h4 ( calculated values )
= 1324.93 - 783.05 = 541.88 kJ/kg
finally determine the network output of the cycle
Wnet = Wt - Wc
= 541.88 - 331.4 = 210.48 kJ/kg
<u>c) determine thermal efficiency </u>
лth = Wnet / qin ------ ( 1 )
where ; qin = h3 - h2
<em>equation 1 becomes </em>
лth = Wnet / ( h3 - h2 )
= 210.48 / ( 1324.93 - 626.57 )
= 0.3014 = 30.14%
