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Vika [28.1K]
4 years ago
10

What is H20 more commonly known as?

Chemistry
1 answer:
Bad White [126]4 years ago
6 0

Answer:

water

Explanation:

The scientific name for water is H2O. It is called H2O because it has two atoms of hydrogen (H) and one atom of oxygen (O)

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acetylene gas c2h2 undergoes combustion to produce carbon dioxide and water vapor How many grams of water are produced by the sa
ella [17]

<u>Answer:</u> The amount of water produced in the given reaction is 0.692x grams.

<u>Explanation:</u>

Let us assume that the initial amount of acetylene gas given be 'x' grams. Now, to calculate the number of moles, we will use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ....(1)

Given mass of acetylene = x grams

Molar mass of acetylene = 26 g/mol

Putting values in above equation, we get:

\text{Number of moles of acetylene}=\frac{xg}{26g/mol}=\frac{x}{26}mol

The reaction of combustion of acetylene is given by the equation:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

By Stoichiometry of the reaction:

2 moles of acetylene produces 2 moles of water.

So, \frac{x}{26} moles of acetylene will produce = \frac{2}{2}\times \frac{x}{26}=\frac{x}{26} moles of water.

Now, to calculate the amount of water produced, we use equation 1:

Molar mass of water = 18 g/mol

Moles of water = \frac{x}{26}mol

Putting values in equation 1, we get:

\frac{x}{26}mol=\frac{\text{Mass of water}}{18g/mol}

\text{Mass of water}=\frac{x}{26}\times 18=0.692x grams

8 0
3 years ago
The difference between GDP and GNP
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GDP measures the value of goods and services produced within a country's borders, by citizens and non-citizens alike. GNP measures the value of goods and services produced by only a country's citizens but both domestically and abroad. GDP is the most commonly used by global economies.
4 0
3 years ago
How do you balance these two chemical equations?
Vlada [557]
In order to balance both of the reactions you need to make sure that both sides of the reaction have the same number of atoms for each atom in order to follow conservation of mass.

KCl+F₂→KF+Cl₂
Notice how in the above reaction there are two chlorine atoms on the products side (right side) and only one atom of chlorine on the reactants side (left side).  you want both the reactants and products side to have the same amount chlorine and to do this multiply KCl by 2.  Fluorine however, has 2 atoms on the reactant side and 1 atom on the product side.  to fix this multiply KF by 2. <span>Therefore the balanced reaction is: 2KCl+F₂→2KF+Cl₂
</span>notice how both sides of the reaction have equal numbers of each atom.

Mg+HCl→MgCl₂+H₂
the above reaction has 2 atoms of H on the products side and only 1 atom of H on the reactants side.  That means you have to multiply HCl by 2.  Now you have the equation Mg+2HCl→MgCl₂+H₂. As you can see now we have equal numbers of all the atoms on both sides which means that that is the balanced equation.

I hope this helps.  Let me know if you have any further questions or need anything to be clarified.
6 0
4 years ago
State 5 negative effects hurtful words can have on people​
Doss [256]
1- can cause insecurities and make people less confident
2- Words can reflect on someone’s mood throughout the day
3- might cause depression or anxiety
4- listening to negative words constantly can make the person’s mind think it’s the truth
5- might change a person
8 0
3 years ago
The compound 1,1-difluoroethane decomposes at elevated temperatures to give fluoroethylene and hydrogen fluoride: CH3CHF2(g) → C
Maru [420]

Answer : The final temperature would be, 791.1 K

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 460^oC = 5.8\times 10^{-6}s^{-1}

K_2 = rate constant at T_2 = 4\times K_1

Ea = activation energy for the reaction = 265 kJ/mol = 265000 J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 460^oC=273+460=733K

T_2 = final temperature = ?

Now put all the given values in this formula, we get:

\log (\frac{4\times K_1}{K_1})=\frac{265000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{733K}-\frac{1}{T_2}]

T_2=791.1K

Therefore, the final temperature would be, 791.1 K

4 0
3 years ago
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