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postnew [5]
2 years ago
13

The difference between GDP and GNP

Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
4 0
GDP measures the value of goods and services produced within a country's borders, by citizens and non-citizens alike. GNP measures the value of goods and services produced by only a country's citizens but both domestically and abroad. GDP is the most commonly used by global economies.
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Find the number of molecules in .815 mole of O2​
Simora [160]

Answer:

4.9 × 10²³ molecules

Explanation:

Given data:

Number of molecules = ?

Number of moles of oxygen = 0.815 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.815 mol  ×  6.022 × 10²³ molecules  / 1 mol

4.9 × 10²³ molecules

6 0
2 years ago
How many moles of co2 are produced when 35.0 mol c2h2 react completely?
Setler [38]

The balanced chemical reaction will be:

C2H2 + 3/2O2 = 2CO2 +H2O

We are given the amount of C2H2 to be burned. This will be our starting point.

<span>35.0 mol C2H2 ( 2 mol CO2/1 mol C2H2) = 70.0 mol O2</span>

<span>Therefore, the CO2 produced is 70.0 moles.</span>

<span>
</span>

7 0
3 years ago
Read 2 more answers
What is the molar concentration of the Cl⁻ ions in 0.64 M MgCl2(aq)?
AlladinOne [14]
We use concentration calculations. MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.64 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
6 0
3 years ago
Which two considerations are used to calculate a windchill factor?
maxonik [38]

Answer:

Air Pressure and Wind direction

Explanation:

Just took the test on e2020

8 0
3 years ago
Read 2 more answers
Determine the pH of a buffer which is a 0.20 M solution of trimethylamine (N(CH3)3) and a 0.40 M solution of trimethylammonium c
uranmaximum [27]

Answer:

pH of the buffer is 10.10

Explanation:

trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.

To determine the pH of the buffer we use H-H equation for weak bases:

pOH = pKb + log [Conjugate acid] / [Weak base]

<em>pKb is -log Kb = 4.20</em>

<em />

pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]

Replacing the concentrations of the problem:

pOH = 4.20 + log [0.20M] / [0.40M]

pOH = 3.90

As pH = 14 -pOH

<h3>pH of the buffer is 10.10</h3>

<em />

7 0
3 years ago
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