Answer:
4.9 × 10²³ molecules
Explanation:
Given data:
Number of molecules = ?
Number of moles of oxygen = 0.815 mol
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
0.815 mol × 6.022 × 10²³ molecules / 1 mol
4.9 × 10²³ molecules
The
balanced chemical reaction will be:
C2H2 + 3/2O2 = 2CO2 +H2O
We are given the amount of C2H2 to be burned. This will be
our starting point.
<span>35.0 mol C2H2 ( 2 mol CO2/1 mol C2H2) = 70.0 mol O2</span>
<span>Therefore, the CO2 produced is 70.0 moles.</span>
<span>
</span>
We use concentration calculations. MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.64 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
Answer:
Air Pressure and Wind direction
Explanation:
Just took the test on e2020
Answer:
pH of the buffer is 10.10
Explanation:
trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.
To determine the pH of the buffer we use H-H equation for weak bases:
pOH = pKb + log [Conjugate acid] / [Weak base]
<em>pKb is -log Kb = 4.20</em>
<em />
pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]
Replacing the concentrations of the problem:
pOH = 4.20 + log [0.20M] / [0.40M]
pOH = 3.90
As pH = 14 -pOH
<h3>pH of the buffer is 10.10</h3>
<em />