Note that the equation of the circle is
(x-h)² +(y-k)² =r²
where centre is (h,k)
the equation of the circle based on the information given
(x-3)² +(y-4)² =r²
and the point on the circle (3,-2)
substitute into the equation
(3-3)² +(-2-4)² =r²
r=6 or r=-6
since r is radius, we reject r=-6 since radius must be nonnegative.
the radius is 6
Answer:
-0.003 %Fahrenheit
Step-by-step explanation:
M(slope)= -5/4 point-slope(y-y1=m(x-x1)) so it would be y-5= -5/4(x+4)
Hello! I believe she would have 58,000 at the end of her fourth year. Hope this helps. :)
<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26