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Tema [17]
3 years ago
15

A 25kg box fell 200m with an acceleration of 5 m/s2. with what force did it hit the floor when it landed?

Physics
1 answer:
Marizza181 [45]3 years ago
6 0
According to Newton's Second Law of motion, the net force acting on the object is equal to its mass multiplied by its acceleration. In formula, it is written as

Net Force =mass * acceleration
Net force = 25 kg * 5m/s^2
Net force = 125 Newtons
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Plz answer my question below....
katrin2010 [14]
It should be YY or Yg
7 0
3 years ago
Name the missing force... Normal <br>   Spring <br>   Tension <br>   Air Resistance
Kay [80]

the missing force is spring force.

The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position.  due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.

the spring force is given as

F = kx

where F = spring force ,k = spring constant , x = stretch in the spring.

the spring force balances the weight of the object in down direction and hence keeps the block from falling down.

4 0
3 years ago
A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
Reil [10]
To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
Centripetal Acceleration = v squared divided by r

where:
v = velocity, m/s
r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
                                      = 81 m/s^2

at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
                                      = 16.2 m/s^2

to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

= 81 m/s^2 - 16.2 m/s^2
= 64.8 m/s^2 or 65 m/s^2
6 0
4 years ago
A certain frictionless simple pendulum having a length l and mass m swings with period t. If both l and m are doubled, what is t
iVinArrow [24]

If l and m both are doubled then the period becomes √2*T

what is a simple pendulum?

It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.

A pendulum is a weight suspended from a pivot so that it can swing freely.

Here,

A certain frictionless simple pendulum having a length l and mass m

mass of pendulum = m

length of the pendulum = l

The period of simple pendulum is:

T = 2\pi \sqrt{\frac{l}{g} }

Where k is the constant.

Now the length and mass are doubled,

m' = 2m

l' = 2l

T' = 2\pi \sqrt{\frac{2l}{g} }

T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }

T' = \sqrt{2} * T

Hence,

If l and m both are doubled then the period becomes √2*T

Learn more about Simple Harmonic Motion here:

<u>brainly.com/question/17315536</u>

#SPJ4

8 0
2 years ago
I can not find the answer to the one after potassium ?
Zepler [3.9K]

Answer:

it’s halogen

Explanation:

3 0
3 years ago
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