Explanation:
(a) Chlorine the first row Is 1s the second is 2s followed by 2p...etc as Chlorine has 17 electrons
We must first write out the entire equation for this reaction which is as follows:
CO + Fe2O3 --> Fe + CO2
Now we must balance this equation which provides us with the following equation:
3 CO + Fe2O3 --> 2Fe + 3 CO2
We are told that we have excess Fe2O3, so that suggests that CO is the limiting reagent. We now simply convert the mass of Fe given to moles of Fe, and convert moles of Fe to moles of CO.
35.0 g Fe/ 55.845 g/mol = 0.627 moles Fe
0.627 moles Fe x (3 moles CO)/(2 moles Fe) = 0.940 moles CO
Now with the moles of CO present, we simply convert this back to mass using the molecular weight of CO.
0.940 moles CO x 28.01 g/mol = 26.3 g CO.
Therefore, 26.3 g of CO are needed to produce 35.0 g of Fe. Since we began with three significant figures in our starting mass, our answer must also have three significant figures.
The answer is: B) Spills in your shop and any releases on pavement or outside should be poured down a drain.
Pouring used oil down a drain can cause damege to environment.
Oil is nonpolar substance and does not dissolve in the water (polar molecule), used oil remain existent in the drain and sewer or in the environment.
Small spills create a cumulative effect with significant impact on the environment.
Untended spills inside a shop can spread to an inside drain connected to the storm sewer system and cause floods.
It’s 140 and it’s also 160
The geometry of a complex is determined by the number of ligands that surround the central atom/ion. There are four ligands in the complex. The coordination number of the complex is 4. The oxidation number of Rh is zero. The preferred geometrical shape of this complex is square planar.
Complexes are formed when Lewis bases called ligands become attached to a central metal atom or ion. The coordination number of the complex refers to the number of ligands that surround the central metal atom/ion.
In this case, four ligands surround the central Rhodium atom in a zero oxidation state.
Since we were told that the compound exhibits cis/trans isomerism then it can not have a tetrahedral geometry. It must have a square planar geometry as tetrahedral complexes do not exhibit cis/trans isomerism.
The image of the cis- and trans- geometrical isomers of the compound is attached to this answer.
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