What are the main pieces of evidence we use to differentiate a black hole binary from a neutron star binary

Which of the following is a use of radioactive isotopes? Question 7 options: a. can determine the ages of rocks and fossils b. c

Zielflug [23.3K]

Answer:

d. all of the above

Explanation:

a) Absolute dating technique is used to determine the age of rocks and fossil fuels, by the use of radioactive elements, such as, Carbon-14. The process involves the measurement of life of fossils through the remaining amount of radioactive element. It is possible by the knowledge of half life of radioactive element.

b) The radioactive isotope of Cobalt (Cobalt-60) is used to treat localized cancer. Other radioactive elements are also used to kill bacteria and treat cancer, such as, Iodine-131 is used to treat thyroid cancer

c) Radioactive elements are also used as tracers, such as Sodium-24, which is used as a tracer in blood. Other radioisotopes of Hydrogen, Carbon. Phosphorus and Sulfur, etc, are also used as tracers in different chemical reactions.

<u>Thus, all the given options are correct and the correct option is all of the above (d).</u>

8 0

4 years ago

Calculate the percentage increase in length of a wire of diameter 2.2 mm stretched by a load of

vesna_86 [32]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

8 0

3 years ago

If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rai

stiks02 [169]

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

$A=13*10^6m^2$

Volume $(V) = A*d = (15*10^6)(0.03) = 3.9*10^5m^3$

t = 3hours=10800s

$\rho = 1000kg/m^3$

From the given data we can calculate the volume of rain for 5 seconds

$V' = \frac{V}{t}*\Delta t_{total}$

Where,

$\Delta t_{total}$ It is the period of time we want to calculate total rainfall, that is

$V' = \frac{3.9*10^5}{10800}*5$

$V' = 1.805*10^2m^3$

Through water density we can now calculate the mass that fell during the 5 seconds:

$m' = V'*\rho$

$m' = 1.805*10^2*1000$

$m' = 1.805*10^5m^2$

Now applying the prevailing equation given we have to

$P=m'v$

$P = (1.805*10^5)(10)$

$P = 1.805*10^6 Kg.m/s$

Therefore the momentum of the rain that falls in five seconds is $1.805*10^6 Kg.m/s$

4 0

3 years ago

When a plane flies with the wind, it can travel 1575 miles in 3.5 hours. when the plane flies in the opposite direction, again

Zepler [3.9K]

When plane is flying along the wind then we can say

$V_{plane} + v_{wind} = \frac{distance}{time}$

$V_{plane} + v_{wind} = \frac{1575}{3.5}$

$V_{plane} + v_{wind} = 450 mph$

Now when its going against the wind the speed is given by

$V_{plane} - v_{wind} = \frac{distance}{time}$

$V_{plane} - v_{wind} = \frac{1575}{4.5}$

$V_{plane} - v_{wind} = 350 mph$

Now by the above two equations we will have

$V_{plane} = 400 mph$

$v_{wind} = 50 mph$

3 0

3 years ago

a very small magnet is wound with 97 layers with 215 turns per layer. how many turns of wire are on the coil?

Kazeer [188]

20855 turns of wire are on the coil.

<h3>What do you mean by a magnet?</h3>

A substance or thing that creates a magnetic field is called a magnet. The most noteworthy characteristic of a magnet—a force that pulls on other ferromagnetic elements, such as iron, steel, nickel, cobalt, etc.—as well as the ability to attract or repel other magnets—is caused by this invisible magnetic field. An object made of a substance that has been magnetized and produces its own persistent magnetic field is referred to as a permanent magnet. A common example is a refrigerator magnet used to keep notes on the door of the refrigerator. Ferromagnetic materials are those that can be magnetized and are also those that are powerfully drawn to a magnet (or ferrimagnetic).

To learn more about the magnet, Visit:

brainly.com/question/12860608

#SPJ4

6 0

2 years ago