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3 years ago

(THIS QUESTION IS FROM APEX IN COURSE: Physical Science Sem 2

Chemistry

2 answers:

Tatiana [17]3 years ago

6 0

Answer: The correct answer is Option A and Option B.

Explanation:

Double displacement reaction is defined as the chemical reaction in which exchange of ions takes place.

The general equation for this reaction follows:

$AB+CD\rightarrow CB+AD$

For the given options:

Option A: $HC_2H_3O_2(aq.)+NaHCO_3(aq.)\rightarrow NaC_2H_3O_2(aq.)+H_2CO_3(aq.)$

This is considered as a double displacement reaction.

Option B: $NaOH(aq.)+HCl(aq.)\rightarrow NaCl(aq.)+HOH(l)$

This is considered as a double displacement reaction.

Option C: $Zn(s)+HCl(aq.)\rightarrow ZnCl_2(aq.)+H_2(g)$

This is considered as a single displacement reaction because more reactive metal (zinc) is displacing a less reactive metal (hydrogen).

Option D: $2Cu(s)+O_2(g)\rightarrow 2CuO(s)$

This is considered as a synthesis reaction because copper and oxygen are combining in their elemental state to produce a single compound.

Hence, the correct answer is Option A and Option B.

mina [271]3 years ago

4 0

The following double-displacement reactions are fully applied/answered:

A. HC2H3O2(aq) + NaHCO3(aq) → NaC2H3O2(aq) + H2CO3(aq)

B. NaOH(aq) + HCI(aq) → NaCI(aq) + HOH(I)

(The answers are A. & B.)

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A flashbulb of volume 2.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 30.0 °C. How many grams of O2(g) doe

Sholpan [36]

P = 2.30 atm

Volume in liter = 2.70 mL / 1000 => 0.0027 L

Temperature in K = 30.0 + 273 => 303 K

R = 0.082 atm

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number of moles O2 :

P * V = n * R* T

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4 years ago

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tangare [24]

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = $V_1=11.00 mL$

Concentration of stock solution = $M_1=0.823 M$

Volume of stock solution after dilution = $V_2=50.00 mL$

Concentration of stock solution after dilution = $M_2=?$

$M_1V_1=M_2V_2$ ( dilution )

$M_2=\frac{0.823 M\times 11.00 mL}{50 ,00 mL}=0.18106 M$

0.18106 M is the molarity of the resulting solution.

Molarity of the solution is the moles of compound in 1 Liter solutions.

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}$

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100 L ( 1 mL=0.001 L)

$Molarity=\frac{13.0 g}{158 g/mol\times 0.100 L}=0.823 mol/L$

0.823 Molar is the molarity of the solution.

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