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LUCKY_DIMON [66]
3 years ago
13

As matter changes, what happens to the energy?

Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

Energy, Temperature, and Changes of State

Matter either loses or absorbs energy when it changes from one state to another. For example, when matter changes from a liquid to a solid, it loses energy. The opposite happens when matter changes from a solid to a liquid.

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What mass of CO is needed to react completely with55.0 g of Fe2O3(s)+CO(g) yield Fe(s)+CO2(g)?
Katarina [22]

Answer:

28.9 g

Explanation:

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Gather all the information in one place</em> with molar masses above the formulas and masses below them.  

M_{r}:     159.69    28.01

              Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂

Mass/g:  55.0

1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

\text{Moles of Fe$_{2}$O$_{3}$} =\text{55.0 g Fe$_{2}$O$_{3}$} \times \frac{\text{1 mol Fe$_{2}$O$_{3}$}}{\text{159.69 g Fe$_{2}$O$_{3}$}}= \text{0.3444 mol Fe$_{2}$O$_{3}$}

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

\text{Moles of CO} = \text{0.3444 mol Fe$_{2}$O$_{3}$} \times \frac{\text{3 mol CO}}{\text{1 mol Fe$_{2}$O$_{3}$}}= \text{1.033 mol CO}

3.Use the molar mass of CO to calculate the mass of CO.

\text{Mass of CO} = \text{1.033 mol CO}  \times \frac{\text{28.01 g CO} }{\text{1 mol CO}}= \textbf{28.9 g CO}  

3 0
3 years ago
Read 2 more answers
How does the molecular formula of a compound differ from the empirical formula? Can a compound’s empirical and molecular formula
Y_Kistochka [10]
Molecular is every element present in the compound eg C2H6, empirical is the smallest whole number ratio of elements in a compound so that would be CH3 as you divide by the highest common factor. Some compounds only have 1 formula if they are simple or have no common factors. Eg methane, CH4 is its molecular and empirical because its the simplest whole number ratio and includes every element in the molecule
4 0
2 years ago
NO LINKS PLEASE! Why does dye dropped into a cup of water eventually spread throughout the water?
Nezavi [6.7K]

Answer:

C

Explanation:

okay, you need to look at the structures of the particles of matter in the solid, liquid and gas.

  • particles in a solid are in fixed positions, where they can only vibrate in those positions ( take a look at ice, or rather, a brick)
  • liquids have very small or rather, no spaces between them, but they can slide or rub against each other, like people in a <em>really tight</em> crowd I guess
  • gas particles have very large spaces between them and they move randomly. these exibit what's called brownian motion.
  • since water particles (and all other liquid particles) have negligible spacings and limited movement, that allows the dye particles to move from a region of high concentration to that of a low concentration. the aim for this is for the mixture/solution to reach an equilibrium, that  is the mixture must get to a point where all regions have the same concentration of the dye.

you can refer to your coursebooks :)

correct where wrong please:)

5 0
2 years ago
Analyze the role coefficients in a chemical reaction play in stoichiometry
kumpel [21]

Answer:

This is known as the coefficient factor

Explanation:The balanced equation makes it possible to convert information about one reactant or product to quantitative data about another element.

7 0
2 years ago
A researcher selects three regions X, Y, and Z, and records the types of discharge that enter the regions’ rivers.
elixir [45]

Region Z should be monitored more closely to avoid health issues.

<h3>Why region Z should be monitored?</h3>

Region Z should be monitored more closely to avoid potential health issues because region Z produces waste from chemical plants which are dangerous for our water and environment so we can conclude that Region Z should be monitored more closely in order to avoid health issues.

Learn more about discharge here: brainly.com/question/4918499

3 0
2 years ago
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