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disa [49]
3 years ago
15

A 500-watt vacuum cleaner is plugged into a 120-volt outlet and used for 30 minutes. How much current runs through the vacuum? 9

00,000 amps 60,000 amps 4.2 amps 0.24 amps
Physics
2 answers:
Anna [14]3 years ago
7 0

Answer:

4.2amps

Explanation:

Iteru [2.4K]3 years ago
4 0

Answer:

The current is 4.2 amp.

(c) is correct option.

Explanation:

Given that,

Power = 500 watt

Voltage = 120 Volt

Time = 30 sec

We need to calculate the current

Using formula of current

P =I\times V

I = \dfrac{P}{V}

Where, I = current

P = power

V = voltage

Put the value into the formula

I=\dfrac{500}{120}

I=4.2\ amp

Hence, The current is 4.2 amp.

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Two boxes on opposite ends of a massless board that is 3.0 m long. The board is supported in the middle by a fulcrum. The box on
rosijanka [135]

Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

s₁ = 1.1 m

Hence, the correct option is:

<u>b. 1.1 m</u>

4 0
3 years ago
If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?
Stella [2.4K]

The density of the material would be 4.1 g/cm³.

Density is calculated by dividing the mass by the volume.

D=m÷v

D=45 g÷11 cm³

D=4.1 g/cm³

3 0
3 years ago
Read 2 more answers
The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
ch4aika [34]

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

7 0
3 years ago
I need help with these Physics problems​
adoni [48]

Answer:

1. 3 m

2. 27 s

Explanation:

1. "A car traveling at +33 m/s sees a red light and has to stop.  If the driver can accelerate at -5.5 m/s², how far does it travel?"

Given:

v₀ = 33 m/s

v = 0 m/s

a = -5.5 m/s²

Unknown: Δx

To determine the equation you need, look for which variable you don't have and aren't solving for.  In this case, we aren't given time and aren't solving for time.  So look for an equation that doesn't have t in it.

Equation: v² = v₀² + 2aΔx

Substitute and solve:

(0 m/s)² = (33 m/s)² + 2(-5.5 m/s²) Δx

Δx = 3 m

2. "A plane starting from rest at one end of a runway accelerates at 4.8 m/s² for 1800 m.  How long did it take to accelerate?"

Given:

v₀ = 0 m/s

a = 4.8 m/s²

Δx = 1800 m

Unknown: t

Equation: Δx = v₀ t + ½ a t²

Substitute and solve:

1800 m = (0 m/s) t + ½ (4.8 m/s²) t²

t ≈ 27 s

4 0
3 years ago
A car of mass 2400kg moving at 20 m/s slams into a cement wall and comes to a halt?
Brut [27]

Impulse = change in momentum

The car's momentum was (mass) x (speed)

Momentum = (2400 kg) x (20 m/s)

Momentum = 48,000 km-m/s

To completely stop the car, the impulse = -48,000 km-m/s .

7 0
4 years ago
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