Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
Answer:
<u>R</u><u>a</u><u>t</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>.</u><u>1</u><u>3</u><u>3</u><u>3</u><u> </u><u>w</u><u>o</u><u>r</u><u>d</u><u>s</u><u> </u><u>p</u><u>e</u><u>r</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u>
Step-by-step explanation:
We understand rating as frequency or speed of doing something per time (seconds mainly)

Let's find rate in terms of seconds (words per second)

Answer:
I hope this is helpful
Step-by-step explanation:
mark brainlest pls
Answer:
(x - 3)(x + 1)(x + 5)
Step-by-step explanation:
I'd use synthetic division instead. If we were to find the roots of the given polynomial, we could from them write the factors as well.
The divisor x + 5 corresponds to root x = -5. Setting up synthetic div.,
-5 ) 1 3 -13 -15
-5 10 +15
-----------------------------
1 -2 -3 0
Since the remainder is 0, we know that -5 is a root and (x + 5) is a factor. Moreover, we know that the coefficients of the quotient are 1, -2 and -3.
1x² - 2x - 3 can be factored: the factors are (x - 3) and (x + 1).
So the end result for this problem is (x - 3)(x + 1)(x + 5).