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2 years ago

Describe the similarities and differences between herbivores,carnivore,and omnivores

Chemistry

1 answer:

vredina [299]2 years ago

3 0

Answer:

Herbivores only eat plants . Remember HERBS are PLANTS.

Carnivores only eat meat. Remember CARNE = MEAT in Spanish.

Omnivores eat MEAT & PLANTS.

Explanation:

Differences are what they eat, similarities omnivores eat both.

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Kc= [3.1*10^-2]^2. (mol/L^2) divide by [8.5*10^-1] [3.1*10^-3]^3 (mol/L)^4

jok3333 [9.3K]

Answer:

Kc = 12.58

Explanation:

Kc = [0.229]^2*[0.687]^6/[0.221]^4*[0.5685]^3

Kc = (0.052441)(0.10513)/(0.002385)(0.18373)

Kc = 0.0005513/0.000438

Kc = 12.58

Hope that helps!!

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2 years ago

Cuantos gramos hay en 3 mol de NaCI?

noname [10]

Answer:

172,5 gramos en 3 moles

Explanation:

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2 years ago

Trying to take the ged test please help me I’m stuck

JulsSmile [24]

Answer: C) Either benzene or oxygen may limit the amount of product that can be formed

Explanation: Benzene and oxygen are the reactants of the equation. What type and the amount of reactants there are in a chemical reaction affects the outcome. Therefore, seeing as benzene and oxygen are the reactants, the answer is C).

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2 years ago

What two elements in the sun mostly made of

ivanzaharov [21]

The sun is made up of two main elements, hydrogen and helium.

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Oxygen, carbon, neon and nitrogen make up most of the remaining 0.2%.

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2 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

2 years ago

Describe the similarities and differences between herbivores,carnivore,and omnivores​

Describe the similarities and differences between herbivores,carnivore,and omnivores