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3 years ago

What is the hybridization and shape for an XeF6 2+ molecule?

Chemistry

1 answer:

VashaNatasha [74]3 years ago

4 0

Answer:

Explained below

Explanation:

An XeF2+ molecule has a linear shape structure with hybridization of sp³d of it's central Xe atom alongside 3 lone pairs of electrons with two bond pairs of electrons.

Meanwhile, XeF6 is different as it possesses a distorted pentagonal bipyramidal shape structure with hybridization of sp³d³ of its central Xe atom with 1 lone pair of electrons alongside 6 bond pairs of electrons.

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Where more of hydrogen are contained in 90 g of water or in 80 g of methane

Lynna [10]

Methane.

Water - H2O
Methane - CH4

Methane has 2 more hydrogens than water.

7 0

3 years ago

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

3 0

3 years ago

What is the compound of KCN called

mash [69]

Potassium Cyanide, is the compound of KCN.

3 0

3 years ago

The correct formula for the diagram is<br>1. 2KO<br>2. K2O<br>3. K2O<br>4. KOK2

Irina18 [472]

Answer:

The diagram provided shows K2O, or potassium oxide.

Explanation:

Ok... so, there are two "K2O" options, so I would just choose either and hope for the best. I don't know, maybe it's a mistake...

8 0

3 years ago

Read 2 more answers

A sample of substance X that has a mass of 326. 0 g releases 4325. 8 cal when it freezes at its freezing point. If substance X h

solmaris [256]

The molar heat of fusion of X has been 775.6 cal/mol. Thus, option C is correct.

The molar heat of fusion has been defined as the energy absorbed or released by a mole of substance in converting between solid and liquid state.

<h3>Computation for the molar heat of fusion</h3>

The given mass of substance X has been, 326 g.

The molar mass of substance X has been 58.45 g/mol.

The moles of sample have been given as:

$\rm Moles=\dfrac{Mass}{Molar\;mass}\\\\ Moles\;X=\dfrac{326\;g}{58.45\;g/mol}\\\\ Moles\;X=5.58\;mol$

Thus, the amount of heat absorbed by 5.58 mol of sample has been 4325.8 cal.

The amount of heat absorbed by a mole of sample has been:

$\rm 5.58\;mol=4325.8\;cal\\\\1\;mol=\dfrac{4325.8\;cal}{5.58\mol} \\\\1\;mol=775.6\;cal/mol$

The amount of heat absorbed by a mole of sample in meting has been the molar heat of fusion.

Thus, the molar heat of fusion of X has been 775.6 cal/mol. Thus, option C is correct.

Learn more about heat of fusion, here:

brainly.com/question/87248

3 0

2 years ago