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Goryan [66]
3 years ago
8

What is the hybridization and shape for an XeF6 2+ molecule?

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Explained below

Explanation:

An XeF2+ molecule has a linear shape structure with hybridization of sp³d of it's central Xe atom alongside 3 lone pairs of electrons with two bond pairs of electrons.

Meanwhile, XeF6 is different as it possesses a distorted pentagonal bipyramidal shape structure with hybridization of sp³d³ of its central Xe atom with 1 lone pair of electrons alongside 6 bond pairs of electrons.

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Do you think it is appropriate to have diet pop available in your school?
pashok25 [27]

Answer:

I think so

Explanation:

It would provide an extra energy boost with lower sugars. Students bring drinks to school anyways so it would be nice to offer some that aren't as detrimental.

3 0
3 years ago
How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal
Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>
8 0
3 years ago
How much heat in j is giving out when 85.0g of lead cools from 200.0 c to 10.0c
photoshop1234 [79]

Answer:

q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.

Explanation:

The Specific Heat capacity of Lead is 0.128 \frac{J}{g\ ^{0}C}

This means, increase in temperature of 1 gm of lead by 1 ^{0}\ C will require 0.128 J of heat.

Formula Used :

q = m.c.\Delta T

q = amount of heat added / removed

m = mass of substance in grams = 85.0 g

c = specific heat of the substance = 0.128

q = m.c.\Delta T = Change in temperature

                                          = final temperature - Initial temperature

                                          = 10 - 200

                                          = -190 ^{0}\ C

put value in formula

q = -  85\times 0.128\times 190

On calculation,

q = - 2067.2 J

- sign indicates that the heat is released in the process

5 0
3 years ago
PLEASE PLEASE PLEASE ANSWER THIS CORRECTLY ASAP 50 POINTS
tresset_1 [31]

If I remember correctly, it would be B. A very large amount of energy is produced from a tremendous mass.

4 0
3 years ago
When electrons are added to the outter most shell of carbon atom it forms
GalinKa [24]

Answer:

An anion that has a larger radius.

Explanation:

3 0
3 years ago
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