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Sergeeva-Olga [200]
3 years ago
15

How many molecules are present in 1.75 moles of dihydrogen monoxide

Chemistry
2 answers:
saveliy_v [14]3 years ago
7 0
The main knowledge you'd have to know to answer this question is the Avogadro's number. It is an empirical data which represents the number of molecules per mole of any substance. It is equal to 6.022*10²³ molecules/mole.

Number of molecules = 1.75 moles*6.022*10²³ molecules/mole = <em>1.054×10²⁴ molecules</em>
omeli [17]3 years ago
5 0
<h2>Answer:</h2>

10.535 ₓ 10²³ molecules

Given data:

Moles of dihydrogen monoxide = 1.75

No. of molecules of dihydrogen monoxide = ?

Solution:

1 mole of solution = 6.02 ₓ 10²³ molecules

1.75 mole of solution = (6.02 ₓ 10²³) ₓ 1.75

                                   = 10.535 ₓ 10²³ molecules

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The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s
kicyunya [14]
The  molar  mass  of    a, b and  c at  STP is calculated  as  below

At  STP  T  is always=   273 Kelvin and ,P= 1.0 atm 

by  use of  ideal  gas  equation  that  is  PV =nRT
n(number   of moles) = mass/molar mass  therefore  replace   n  in  the  ideal   gas  equation

that  is Pv = (mass/molar mass)RT
multiply  both side  by molar  mass  and  then  divide  by  Pv  to  make  molar mass the  subject of the  formula

that is  molar  mass =  (mass x RT)/ PV

 density is always = mass/volume

therefore  by  replacing  mass/volume  in   the equation  by  density the equation
molar  mass=( density  xRT)/P  where R  =  0.082 L.atm/mol.K

the  molar mass  for  a
= (1.25 g/l  x0.082 L.atm/mol.k  x273k)/1.0atm = 28g/mol

the molar  mass of b
=(2.86g/l  x0.082L.atm/mol.k   x273  k) /1.0  atm  = 64  g/mol

the molar  mass of c

=0.714g/l  x0.082  L.atm/mol.K  x273 K) 1.0atm= 16 g/mol

therefore  the 
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8 0
3 years ago
A gas occupies 18.5L at stp. what volume will it occupy at 735 torr and 57°c?
olga nikolaevna [1]

 The volume that  will  be occupied at 735  torr and 57 c  is 23.12 L


 <u><em>calculation</em></u>

  • <u><em> </em></u> At STP   temperature=273 k  and  pressure=760 torr
  • <u><em> </em></u>by use of combined  gas formula

that is P1V1/T1= P2V2/T2

where; P1 =760 torr

           T1= 273  K

           V1= 18.5 L

          P2= 735 torr

         T2=  57+273= 330 K

          V2=?

  • by making   V2 the formula of subject

     V2= T2P1V1/P2T1

       V2=  [(18.5L  x 330 k  x 760 torr)/(735 torr x 273 k)]= 23.12  L




5 0
3 years ago
There are two groups of waves with the same amplitude. One contains waves of short wavelength and the other has waves of long wa
jolli1 [7]

Answer:

i think the long wavelength has more energy

Explanation:

plz correct me if i'm wrong

3 0
3 years ago
Read 2 more answers
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