Answer:
The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum level for which the battery pack will be classified as highly sought-after class
At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.
The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours
Answer:
Step-by-step explanation:
Since we know the slope and a point, we can use the point-slope form.
The point-slope form is:
Substitute 8 for m, and let (-4,-3) be x₁ and y₁, respectively. Thus:
Simplify:
Distribute:
Subtract 3 from both sides:
And we're done!
Let A unit be a; B unit be b
a + b = 95
b = 95 - a
3a + 5b = 395
3a + 5(95 -a) = 395
3a + 475 - 5a = 395
-2a = -80
a = 40
a + b = 95
40 + b = 95
b = 55
Therefore, a = 40; b = 55.
Hope this helps
Answer:
(9-10x)(9+10x) (I think this is the answer but I'm not one hundred percent sure)
Step-by-step explanation:
First, you can recognize that both numbers (-100x^2 and 81) are a difference of squares, in which means that they both can be square routed. Then, plug in the square routes of the numbers into (9-10x)(9+10x). 9 is the square route of 81 and 10 is the square route of 100. Make sure that when you put the numbers in the parenthesis that there is one negative and positive number since a negative multiplied by a positive makes a negative, hence making 100 negative. I hope that helped.
Answer:
see explanation
Step-by-step explanation:
Given f(x) then the derivative f'(x) is
f'(x) = lim(h tends to 0 ) 
= lim ( h to 0 ) 
= lim ( h to 0 ) 
= lim( h to 0 ) 
= lim( h to 0 ) 
= lim ( h to 0 ) 
← cancel h on numerator/ denominator
= lim ( h to 0 ) 4(2x + h) ← let h go to zero
f'(x) = 8x
