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kvv77 [185]
3 years ago
10

Snape and Dumbledore both agree that safety must be a priority. Before we get into the more challenging questions they think we

should review some safety practices. For the reactivity of metals experiment which of the following is a laboratory safety precaution? Please read all the choices before choosing an answer.A) Since you will be working with hydrochloric acid (6M) care must be exercised not to get this acid on your clothes or skin. If you should come into physical contact with it, wash if off as fast as possible with copious amounts of water. Then inform your teaching assistant of your spill.B) You must wear goggles in this laboratory.C) Handle your thermometer with care. When you remove it from your drawer be sure to hold both ends of the thermometer so that it does not slip out.D) No flames of any type will be permitted in the laboratory while this experiment is being performed.
Chemistry
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

The correct answer is option C) "Handle your thermometer with care. When you remove it from your drawer be sure to hold both ends of the thermometer so that it does not slip out".

Explanation:

Handling a thermometer with care is part of the laboratory safety precautions that should be considered regarding to the reactivity of metals. Old thermometers are based on the element mercury, a shining metal that is the only element that is in liquid state on room temperature conditions. Mercury is very toxic, and is particularly dangerous because it vaporizes at room temperature and it could be inhaled.

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At a certain temperature, 0.4011 mol of N 2 and 1.501 mol of H 2 are placed in a 3.00 L container. N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽
kenny6666 [7]

Answer:

Kc = 16.6

Explanation:

Step 1: Data given

Number of moles N2 = 0.4011 moles

Number of moles H2 = 1.501 moles

Volume = 3.00 L

At equilibrium, 0.1801 mol of N 2 is present

Step 2: The balanced equation

N2(g) + 3H2(g) ⇆ 2NH3(g)

Step 3: Calculate amount of N2 reacted

moles N2: 0.4011 mol - 0.1801 mol = 0.221 mol

For 1 mol N2 therewill react 3 moles of H2 to produce 2moles of NH3

Moles H2 reacted= 3 * 0.221 mol = 0.663 mol es

Moles NH3 produced = 2 * 0.221 mol = 0.442 mol es

Step 4: Amount of moles at equilibrium

Moles N2 = 0.1801 mol

[N2] = 0.1801 mol / 3.0 L = 0.06003 M

Moles H2 =1.501 moles - 0.663 mol = 0.838 moles

[H2] = 0.838 moles / 3.0 L = 0.2793 M

Moles NH3 = 0.442 mol

[NH3] = 0.442 mol / 3.0 L = 0.1473 M

Step 5: Calculate Kc

Finally, we can calculate Kc:

Kc = [NH3]² / ([N2] [H2]³)

Kc = (0.1473²)/(0.06003 *0.2793³)

Kc = 16.6

5 0
3 years ago
Is slime a solid or liquid?
Ivan

Answer:

i think its a liquid..... im not that sure

7 0
3 years ago
Consider the following reaction of calcium hydride (CaH2) with molten sodium metal: CaH2(s) 2 Na(l) -> 2 NaH(s) Ca(l) Identif
pashok25 [27]

Answer:

None of the species in the equation have undergone either oxidation or reduction

Explanation:

The easiest way to see if oxidation or reduction has happened is to compare oxidation numbers of each and every species before and after the reaction.

Calcium is two before the reaction and two after the reaction

Hydrogen is -1 before the reaction and -1 after the reaction

Sodium is one before the reaction and one after the reaction

Iodine is -1 before the reaction and -1 after the reaction.

For an oxidation to happen an increase in oxidation number has to happen.

For a reduction to happen, a decrease in oxidation number has to happen. None have happened

8 0
3 years ago
A chemistry student needs 45.0mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stud
Masja [62]

The mass of pentane the student should weigh out is

The density of pentane is 0.626 gcm-3

To calculate the mass of pentane following expression is used,

(Density is defined as the mass divide by volume)

Density = mass / volume

mass of pentane = Density of pentane * Volume of pentane

mass of pentane = 0.626 gcm-3 * 45.0 mL

                             = 28.17 g

Here the unit of mass of pentane is g,

However the unit of density is gcm-3 and unit of volume is mL i.e. cm3

Hence,   Mass = gcm-3 * cm3

              Mass = g

The mass of pentane the student should weigh out is 28.17g

Learn more about Density on

brainly.com/question/1354972

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5 0
2 years ago
What is the molar mass of Iron (ll) Hydroxide, Fe(OH)2.
Tanzania [10]

FeOH2 = 73.8602753 g/mol

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

4 0
3 years ago
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