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inessss [21]
3 years ago
5

how many moles of silicon are in 245 g of silicon? a. 8.72 mol b. 28.0 mol c. 1.10 × 10-1 mol d. 6.90 × 103 mol

Chemistry
2 answers:
il63 [147K]3 years ago
8 0
Atomic mass silicon = 28.085 u

1 mol Si ---------------- 28.085 g  
?  ------------------------ 245 g

245 x 1 / 28.085 => 8.72 mol

answer A
skad [1K]3 years ago
5 0

Answer:

The answer to How many moles of silicon are in 245 g of silicon? is:

a. 8.72 mol

Explanation:

To resolve this problem, we need to know the Silicon atomic weight, we can find this information in  the periodic table of elements

Si= 28.0855 \frac{g}{mol}

This means that for every mole, there are 28.0855 grams of Silicon

Now, with this information we can find the answer to this problem:

245 g*\frac{1 mol}{28.0855 g} = 8.72 mol of Silicon

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<span>Answer: 0.094%


</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />

<span>Only the ionization of the formic acid is the important part.
</span><span />

<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />

<span>2) Mass balance:
</span><span />

<span>                   HCOOH(aq)     HCOO⁻(aq)     H⁺(aq).

Start             0.311                 0.189

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Final             0.311 - x          0.189 + x            x


3) Acid constant equation:
</span><span />

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4) Solve the equation:


You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />

<span>With that approximation the equation to solve becomes:


</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M


5) With that number, the percent of ionization (alfa) is:
</span><span />

<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
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