Answer:
+1.03 V
Explanation:
The standard emf of the voltaic cell is the value of the standard potential of it, which is calculated by the standard reduction potential (E°).
The standard reduction potential is the potential needed for the reduction reaction happen, and it's determined by the reaction with the hydrogen cell (which has E° = 0.0V). The half-reactions of reduction of Ni⁺² and Ag⁺, are:
Ni⁺²(aq) + 2e⁻ → Ni(s) E° = -0.23 V
Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V
The value is calculated by a spontaneous reaction, in which the cell with the greater E° is reduced (gain electrons), and the other is oxidized (loses electrons). So, Ag⁺ reduces.
emf = E°reduces - E°oxides
emf = 0.80 - (-0.23)
emf = +1.03 V
Blue litmus paper turning red means that the solution where the litmus paper was submerged is an acidic solution with a pH of less than 7. Another verification of the nature of the solution is the turning to red of methyl orange in acidic solutions. The answer then is D.
Answer:
C) Fluorine has the strongest tendency to attract electrons.
Explanation:
Electronegativity is the tendency of the atom in a covalent bond to attract the shared pair of electron towards itself.
Down the group, size increases which means that the nucleus become far from the valence electrons and thus decreased electronegativity as there will be less tendency to attract the shared electrons.
Fluorine and iodine are in the same group and thus fluorine has higher tendency to attract electrons and thus has the highest electronegativity.
<span>C6H12O6 + O2 --> CO2 +H2O </span>
<span>In the balancede form we have: </span>
<span>C6H12O6 + 6O2 ---> 6CO2 + 6H2O </span>
<span>C -6 , H -12 and O - 18 </span>
<span>in both sides.</span>
