Answer:
Q < Ksp
Explanation:
The general equilibrium of a constant product solubility, ksp, is:
AB ⇄ A⁺ + B⁻
<em>Where Ksp is defined as:</em>
Ksp = [A⁺] [B⁻]
When [A⁺] [B⁻] = Ksp, the solution is saturated or oversaturated because there are the maximum amount of ions that solution can dissolve.
When the solution is oversaturated, AB is produced.
Now, in a unsaturated solution, the [A⁺] [B⁻] is less than the maximum amount that can be dissolved. That means:
[A⁺] [B⁻] = Q < Ksp
Q is defined in the same way than Ksp, just in Q the system is not in equilibrium.
Right answer is:
<h3>Q < Ksp</h3>
Answer:
This is very easy Cuz We have 2Na2O We have O2 so thats molecule of Oxygen and its same on product We need to balance Na on start We have 1 on product We have 2 so Just put 2 at start....
Explanation:
Sorry for bad english not my first language :(
2Na+O2-->2Na20
Answer:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Explanation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)
A careful observation of the equation above, shows that the equation is already balanced.
To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
