Answer:
The osmotic pressure is 6.26 atm
Explanation:
Step 1: Data given
Mass of testosterone = 12.4 grams
Volume of benzene = 168 mL
Temperature = 298 Kelvin
Step 2: Calculate moles of testosterone
Moles testosterone = mass / molar mass
Moles testosterone = 12.4 grams / 288.42 g/mol
Moles testosterone = 0.0430 moles
Step 3: Calculate molarity
Molarity = moles / volume
Molarity = 0.0430 moles / 0.168 L
Molarity = 0.256 M
Step 4 : Calculate the osmotic pressure
π = iMRT
⇒ with i = The Van't hoff factor = 1 (since testosterone is nonelectrolyte)
⇒ with M = the molair concentration = 0.256 M
⇒ with R = the gas constant = 0.08206 L*atm/k*mol
⇒ with T = the temperature = 298 K
π = 1*0.256*0.08206*298
π = 6.26 atm
The osmotic pressure is 6.26 atm
