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almond37 [142]
3 years ago
9

13. What is the total pressure inside the container​

Chemistry
1 answer:
nasty-shy [4]3 years ago
7 0

<u>Answer:</u> The total pressure inside the container is 77.9 kPa

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the total pressure inside the container, we use the law given by Dalton, which is:

P_T=p_{N_2}+p_{O_2}+p_{Ar}

We are given:

Vapor pressure of oxygen gas, p_{O_2} = 40.9 kPa

Vapor pressure of nitrogen gas, p_{N_2} = 23.3 kPa

Vapor pressure of argon, p_{Ar} = 13.7 kPa

Putting values in above equation, we get:

p_T=23.3+40.9+13.7\\\\p_{T}=77.9kPa

Hence, the total pressure inside the container is 77.9 kPa

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Which of the following is not equal to 42.7 millimeters?
Stella [2.4K]

The answer is: C. 0.00427 m.

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d = 0.0000427 km · 1000000 mm/km.

d = 47.7 mm.

B) 1 hm = 100000 mm.

d = 0.000427 hm · 100000 mm/hm.

d = 42.7 mm.

C) 1 m = 1000 mm.

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8 0
3 years ago
Explain why the place of aluminum in the reactivity wagon seems to be unsuitable.
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Answer:

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Explanation:

5 0
2 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
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