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4 years ago

I need help on question 2

Mathematics

2 answers:

Julli [10]4 years ago

8 0

Well it goes in an odd patter like 5,3,1,3,5 so the first one would be -2

Luden [163]4 years ago

4 0

I do not know sorry i tryed

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What is the value of x???

lbvjy [14]

cross multiply

20x = 7.4 * 73

x = (7.4 * 73) / 20 = 27.01 answer

5 0

3 years ago

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if the roots of the equations(given in the picture as question no. 3) are simultaneously real then prove that b2=ac

makkiz [27]

Hi,
1) ax²+2bx+c=0 have real roots then (2b)²-4ac>=0 ==> 4b²>=4ac ==> b²>=ac
2) bx²-2√(ac)x+b=0 have real roots then
(-2√(ac))²-4b²>=0==> 4ac>=4b²==> ac>=b²
So b²>=ac>=b²==> b²=ac

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4 years ago

The length of a particular rectangle is 4 greater than the width of the rectangle. If the perimeter of the rectangle is 16, what

Nuetrik [128]

2l+2w=perimeter <= equation for perimeter
w+4=l <=length is 4 greater than width 
2w+2(w+4)=24 <= plug in the l in the first equation with the second equation 
2w+2w+8=24 <= solve the equation 
4w=16 
w=4 
and, since 
w+4=l <= length is 4 greater than width 
then l=4+4 
l=8

4 0

4 years ago

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Can somebody number the problem and work it out for me thanks and btw it’s solving system by graphics

adoni [48]

Answer:

Solutions are (3,1) and (4,2)

Step-by-step explanation:

Graph is shown in the attached sheet

Given are two systems of equations and we have to solve them using graph

For graphing let us first prepare table for x and y.

1) $y=\frac{-2x}{3} +3:\\y=2x-5$

I line II line

x 0 4.5 3 x 0 2.5 3

y 3 0 1 y -5 0 1

The two lines intersect at (3,1)

Hence solution is (3,1)

--------------------------------------------

2) $y=\frac{x}{2} \\-6x+3y=-18$

I line II line

x 0 2 4 x 0 6 4

y 0 1 2 y 3 0 2

The two lines intersect at (4,2)

Hence solution is (4,2)

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3 years ago

Harvey invested $6000 for 2 years in a savings account paying simple interest with a yearly interest rate of 5.5%. How much simp

pogonyaev

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$6000\\
r=rate\to 5.5\%\to \frac{5.5}{100}\to &0.055\\
t=years\to &2
\end{cases}
\\\\\\
I=6000\cdot 0.055\cdot 2$

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4 years ago

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