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Gre4nikov [31]
4 years ago
14

BRAINLIEST GODS HELP!!!!! At work one day, Robert DJ received 22 packages. Speedy delivery delivered four times as many as Jenna

s express I’ll generous express deliver to more than send quick package service how many packages did each service deliver it to Robert?
Mathematics
1 answer:
Law Incorporation [45]4 years ago
5 0

At work one day, Robert DJ received 22 packages. Speedy delivery delivered four times as many as Jenna’s Express, while Jenna’s Express delivered two more than SendQuick package service. How many packages did each service deliver to Robert DJ?

We'll call the number of packages delivered by the respective services s, j, and q for Speed, Jenna and SendQuick.

Robert DJ received 22 packages:

s + j + q = 22

Speedy delivery delivered four times as many as Jenna’s express.

s = 4j

Jenna’s Express delivered two more than SendQuick

j = 2q

Substituting,

22 = s + j + q = 4 j + j + q = 5j + q = 5(2q) + q = 11 q

q = 22/11 = 2

j = 2q = 4

s = 4j = 16

Check: 2+4+16=22 good

Answer: Speedy: 16, Jenna: 4, SendQuick: 2


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Every <u>hexagon </u>tessellates.

Step-by-step explanation:

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3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

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Step-by-step explanation:

  1. Multiply: 23*3
  2. 23*3=69
  3. Add: 69+1
  4. 69+1=70
  5. 70/3

<em>Hope this helped!! :)</em>

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