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lisov135 [29]
3 years ago
5

You are beautiful have a nice day <3​

Physics
2 answers:
GrogVix [38]3 years ago
8 0

Answer:

AWWW! Thanks! you as well!

Explanation:

Tresset [83]3 years ago
7 0

Answer:

I am?

Explanation:

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Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the fo
belka [17]
A-It will be one-ninth the original force
3 0
3 years ago
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Which element has 7 valence electrons?
Kruka [31]

Answer:

Bromine

Explanation:

because it is present in 17th group that gives valence electrons as 7 in its last orbit

4 0
2 years ago
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A jet moving at 500.0 km/ h due is in a region where the wind is moving at 120.0 km/h in a direction 30.00° north of east. What
WARRIOR [948]

Answer:

The speed of the aircraft relative to the ground is 606.9 m/s^2

Explanation:

x-y coordinate system:  

x is Positive due East direction. Similarly  y is Positive due North Direction.

Now let us Decompose each vector into x-y

500 km/h due east = (500, 0)

120 km/h at 30 degree north of east

= (120 cos(30), 120 \times sin(30))

= (120 \times \frac{\sqrt{(3)}}{2}, 120 \times \frac{1}{ 2})

= (60 \times \sqrt(3), 60)

Adding  the vectors.

=(500, 0) + (60 \times \sqrt{3}, 60)

=(500 + 60 \times \sqrt(3), 60)

=(500 + 60 \times 1.73, 60)

=(500 +103.8, 60)

= (603.8, 60)

Returning back to polar form

Magnitude = \sqrt{603.923^2 + 60^2} = 606.9

7 0
4 years ago
A wave is traveling at a speed of 12m/s and its wavelength is 3 m calculate the wave frequency
White raven [17]

Answer:

f = 4 Hz

Explanation:

Given that,

The speed of a wave, v = 12 m/s

The wavelength of a wave, \lambda=3\ m

We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz

So, the frequency of the wave is equal to 4 Hz.

6 0
3 years ago
An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
7 0
3 years ago
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