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Vika [28.1K]
3 years ago
11

Solve 10N x 1m = 10)

Chemistry
1 answer:
stellarik [79]3 years ago
5 0

Answer:

=10 joules

when multiplying with newtons ( the unit of force)

by a perimeter, it will becone joules, but the specific amount depends on how many newtons and metres there are

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The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
2 years ago
According to the rate law (rate = k[a]m[b]n), what does the rate of a reaction depend on?
Andreyy89
Concentration of the reactant,pressure,surface
 area of the reactant  and temperatur
8 0
3 years ago
Choose the pair in which the components have the same charge. question 6 options: a proton and a hydrogen atom a hydrogen atom a
worty [1.4K]

Answer:

           A Neutron and a Hydrogen Atom

Explanation:

                   Hydrogen atom having an atomic mass of 1.008 amu consists of one proton and one electron. Hence, the +ve and -ve charges cancels out and makes the hydrogen atom a neutral specie.

                    Also, we know that neutron is neutral sub particle while, proton and electron are positively and negatively charged respectively. Therefore, a neutral neutron having no charge becomes equal to hydrogen atom having zero charge due to cancellation of both +ve and -ve charges.

8 0
3 years ago
Which is one way scientists indicate how precise And accurate their experimental measurements are?
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<span>. They make sure their experiments can be repeated</span>
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3 years ago
In this experiment, 0.070 g of caffeine is dissolved in 4.0mL of water. The caffeine is extracted from the aqueous solution thre
Len [333]

Answer:

0.068 g

Explanation:

The equation that is used to determine the fraction q remaining in water of volume V₁ after n extractions of volume V₂ is:

qⁿ = (V₁/(V₁ + KV₂))ⁿ

Substituting in the values gives the fraction of caffeine left in the water phase:

q³ = (4.0mL/(4.0mL + 4.6(2.0mL))³ = 0.0278

The fraction of caffeine extracted into the methylene chloride phase is:

1 - 0.0278 = 0.972

The amount of caffeine extracted into the methylene chloride is:

(0.070g)(0.972) = 0.068 g

6 0
3 years ago
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