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Viefleur [7K]
2 years ago
7

Can 24/7 be simplified into a smaller fraction?

Mathematics
2 answers:
dimaraw [331]2 years ago
6 0

Answer:

No

Step-by-step explanation:

It can't because no number goes into 24 and 7, and 7 does not go its 24

Novosadov [1.4K]2 years ago
6 0

yes It can 3 3/7 it can be simplified to

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LUCKY_DIMON [66]

Answer:

Part A: $6.76

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Step-by-step explanation:

33.8/5 = 6.76

27.04(5) = 135.2

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3 years ago
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The distance around a triangle is 46 ft the length 12 what is the width
Juliette [100K]

Answer:

22

Step-by-step explanation:

12+12=24

46-24=22

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2 years ago
Kristen goes on a cave tour with her family. they climb down to 8 meters below ground level
dybincka [34]

Answer:

16 meters

Step-by-step explanation:

Step 1:

They climbed 8 meters down

Then 8 meters up to get back to ground level.

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3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

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2 years ago
Sean tried to drink a slushy as fast as he could. He drank the slushy at a constant rate. There were originally 275 milliliters
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Answer: A and B

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