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3 years ago

What is the difference between repetition and replication of an investigation

1 answer:

4 0

Repetition is repeating the same investigation over and over again . Such as you doing an experiment and redoing to to see if you get the same results however it is often confused with replication . Replication is when you copy an experiment done by someone else . Such as seeing an experiment and trying to get the same results as someone . Repetition you often do yourself while replication you copy someone else .

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What are the number of protons, neutrons, and electrons in an atom of Tellurium- 129?

deff fn [24]

Answer:

Number of protons = 52, Number of electrons = 52, Number of neutrons = 76

Explanation:

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3 years ago

Darwin called this idea of certain traits being selected in order for an organism to reproduce sexual selection. In crickets and

tamaranim1 [39]

Th correct answer is option C. Calling can be hazardous because it also attracts parasites and predators.

The mating call is used by the males to attract females for sexual reproduction. By using vocal sounds males are not only making themselves attractive to females, they are also making themselves vulnerable to predators.

Thus the mating call can have a disastrous effect on the survival of the species.

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3 years ago

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Which method of heat transfer is due to the transfer of kinetic energy from one molecule to another?

pshichka [43]

Answer: Conduction

Explanation:

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3 years ago

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How can I find the answer for this ?

12345 [234]

For what? what is your question

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3 years ago

For the reaction

s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

Given parameters:

Molar mass of SO₃ = 80.0632g/mol

Mass of S = 17.9g

Molar mass of S = 32.065g/mol

Number of moles of O₂ = 0.157mole

Molar mass of O₂ = 31.9988g/mol

Unknown:

Maximum amount of SO₃

Solution

We need to write the proper reaction equation.

2S + 3O₂ → 2SO₃

We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.

So we simply compare the molar relationship between sulfur and product formed to solve the problem:

First, find the number of moles of Sulfur, S:

Number of moles of S = $\frac{mass }{molar mass}$

Number of moles of S = $\frac{17.9 }{32.065}$ = 0.558mole

Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:

2 mole of Sulfur produced 2 mole of SO₃

Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃

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3 years ago