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3 years ago

What is the difference between repetition and replication of an investigation

1 answer:

4 0

Repetition is repeating the same investigation over and over again . Such as you doing an experiment and redoing to to see if you get the same results however it is often confused with replication . Replication is when you copy an experiment done by someone else . Such as seeing an experiment and trying to get the same results as someone . Repetition you often do yourself while replication you copy someone else .

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For the neutralization reaction involving hno3 and ca(oh)2, how many liters of 1. 55 m hno3 are needed to react with 45. 8 ml of

Agata [3.3K]

For the neutralization reaction involving HNO₃ and Ca(OH)₂, liters of 1.55 M HNO₃ are needed to react with 45.8 ml of a 4.66 m Ca(OH)₂ solution is 0.270 L.

<h3>What is neutralization reaction?</h3>

Those reactions in which acids and bases will combine with each other for the formation of water molecule and salt, is known as neutralization reaction.

Given chemical reaction is:

2HNO₃ + Ca(OH)₂ → 2H₂O + Ca(NO₃)₂

Moles (n) of Ca(OH)₂ will be calculated by using the below formula:
M = n/V, where

M = molarity = 4.66M

V = volume = 45.8 mL = 0.045 L

n = (4.66)(0.045) = 0.2097 mol

From the stoichiometry of the reaction,

1 mole of Ca(OH)₂ = reacts with 2 moles of HNO₃

0.2097 mole of Ca(OH)₂ = reacts with 2×0.2097=0.419 moles of HNO₃

Again by using the molarity equation volume will be calculated for HNO₃ as:

V = (0.419) / (1.55) = 0.270 L

Hence required volume of HNO₃ is 0.270 L.

To know more about neutralization reaction, visit the below link:

brainly.com/question/23008798

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6 0

2 years ago

What would be the concentration of a solution resulting when you dissolve 4.725g of nacl (molar mass = 58.45) in water to make a

aliya0001 [1]

<span>There are a number of ways to express concentration of a solution. This includes molarity. It is expressed as the number of moles of solute per volume of the solution. To convert the mass of the solute to moles, we use the molar mass of the substance. We calculate as follows:

MOlarity = 4.725 g ( 1 mol / 58.45 g ) / .5 L = 0.162 mol / L</span>

3 0

2 years ago

a compound has a percent compostion of carbon equal to 48.8383%, hydrogen equal to 8.1636%, and oxygen equal to 43.1981%. what i

Margarita [4]

Answer:

C₂H₃O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 48.8383%

Hydrogen (H) = 8.1636%

Oxygen (O) = 43.1981%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 48.8383%

H = 8.1636%

O = 43.1981%

Divide by their molar mass

C = 48.8383 / 12 = 4.07

H = 8.1636 / 1 = 8.1636

O = 43.1981 / 16 = 2.7

Divide by the smallest

C = 4.07 / 2.7 = 2

H = 8.1636 / 2.7 = 3

O = 2.7 /2.7 = 1

Thus, the empirical formula of the compound is C₂H₃O

8 0

3 years ago

Match the Terms to their definition:

olganol [36]

1. B
2. H
3. G
4. I
5. D
6. C
7. A
8. F
9. E
I am not sure weather it is correct but I wrote what I know

3 0

3 years ago

Read 2 more answers

Can someone help please

enyata [817]

Answer:

d. cells are made of atoms and molecules. :)

Explanation:

hope i helped

8 0

2 years ago

Read 2 more answers