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tresset_1 [31]
3 years ago
14

What is the difference between repetition and replication of an investigation

Chemistry
1 answer:
schepotkina [342]3 years ago
4 0
Repetition is repeating the same investigation over and over again . Such as you doing an experiment and redoing to to see if you get the same results  however it is often confused with replication . Replication is when you copy an experiment done by someone else . Such as seeing an experiment and trying to get the same results as someone . Repetition you often do yourself while replication you copy someone else .
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21 Given the following acid dissociation constants, which acid has the strongest conjugate base?
Makovka662 [10]
The correct answer is HCN.
7 0
2 years ago
Elements listed in vertical columns of the periodic table:
marysya [2.9K]
Vertical columns are called groups, or families. 

They share similar chemical properties. 

Answer: <span>have similar chemical properties</span>
3 0
3 years ago
Read 2 more answers
How much water would need to be added to 1092 mL of a 54.7 M NaCl solution to make a 0.25 M solution?
babunello [35]

Answer:

237.8L of water would need to be added.

Explanation:

The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).

Then figure out what information you have and what is being found. In this case:

M1 = 54.7 M

V1 = 1092 mL = 1.092 L

M2 = 0.25 M

V2 = unknown

Then solve the equation for whatever you are trying to find.

M1V1=M2V2

V2=M1V1/M2

Now you need to plug everything in.

V2=(54.7M*1.091L)/0.25M

V2=238.93L

That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.

238.93L - 1.091L = 237.8L

Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.

I hope this helps.  Let me know if anything is unclear.

8 0
2 years ago
Need help with the balancing one
DochEvi [55]
The third option, 2,2,1,2
8 0
2 years ago
Draw a Lewis structure for HCCl3 . Include all hydrogen atoms and show all unshared pairs and the formal charges, if any. Assume
andrey2020 [161]

Answer:

See answer below

Explanation:

First, let's explain what a Lewis structure is.

A lewis structure in short words is a draw of an atom or molecule showing how the electrons bond with another electrons of atoms, and also shows the unshared pair of electrons, which are the electrons that do not bond in the molecule. In the case of an atom, it shows all the available electrons it has to be shared and bonded with another atom to form a molecule.

With this said, in order to draw the lewis structure we need to know how many electrons the atoms involved have. To know this, we need to write the electronic configuration of the atoms, based on it's atomic number.

In the case of Hydrogen (Z = 1), Carbon (Z = 6) and Cl (Z = 17):

[H] = 1s¹     1 electron available.

[C] = 1s² 2s² 2p²   In this case, we have 4 electrons.

[Cl] = 1s² 2s² 2p⁶ 3s² 3p⁵  In this case, 7 electrons.

Now that we have the configuration, and the available electrons, we need to draw the atoms. The Carbon is the more electronegative atom of them, so, the bonding will be formed based on this atom as the central. So the other atoms will just bond and shared a pair of electron with the carbon. The HCCl₃ can be treated as CH₄, with a tetrahedrical form.

The picture below shows the lewis structure.

Hope this helps

3 0
3 years ago
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