Answer:Even if your door is closed, you would still smell the odors because of the space under the door and the space that is needed to close the door.
Explanation:
The maximum amount of XeF4 that could be produced is 0.5 moles.
XeF4 = Xe (g) 2 F2 (g) (g)
Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.
<h3>What is mole ratio?</h3>
The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.
A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.
A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.
To learn more about mole ratio from the given link:
brainly.com/question/14425689
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1 valence electron in alkali metals.
Answer:
18.0 Ampere is the size of electric current that must flow.
Explanation:
Moles of electron , n = 550 mmol = 0.550 mol
1 mmol = 0.001 mol
Number of electrons = N
![N=N_A\times n](https://tex.z-dn.net/?f=N%3DN_A%5Ctimes%20n)
Charge on N electrons : Q
![Q = N\times 1.602\times 10^{-19} C](https://tex.z-dn.net/?f=Q%20%3D%20N%5Ctimes%201.602%5Ctimes%2010%5E%7B-19%7D%20C)
Duration of time charge allowed to pass = T = 49.0 min = 49.0 × 60 seconds
1 min = 60 seconds
Size of current : I
![I=\frac{Q}{T}=\frac{N\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BQ%7D%7BT%7D%3D%5Cfrac%7BN%5Ctimes%201.602%5Ctimes%2010%5E%7B-19%7D%20C%7D%7B49.0%5Ctimes%2060%20seconds%7D)
![=\frac{n\times N_A\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bn%5Ctimes%20N_A%5Ctimes%201.602%5Ctimes%2010%5E%7B-19%7D%20C%7D%7B49.0%5Ctimes%2060%20seconds%7D)
![I=\frac{0.550 mol\times 6.022\times 10^{23} mol^{-1}\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}=18.047 A\approx 18.0 A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B0.550%20mol%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%20mol%5E%7B-1%7D%5Ctimes%201.602%5Ctimes%2010%5E%7B-19%7D%20C%7D%7B49.0%5Ctimes%2060%20seconds%7D%3D18.047%20A%5Capprox%2018.0%20A)
18.0 Ampere is the size of electric current that must flow.
V
1
/T
1
=V
2
/T
2
(900.0 mL) / (300.0 K) = (x) / (405.0 K); x = 1215 mL.
Change the 900 to 800, and the 300 to 27, then change the 405 to 132. And solve