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gtnhenbr [62]
2 years ago
10

How much he is given out 185 g of lead cools from 200 Celsius to 10 Celsius

Physics
1 answer:
ioda2 years ago
5 0

Given data

mass (m) = 185 g  = 0.185 Kg ,

temperature (T₁) = 200°C = 200 + 273 = 473 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k

                <em>Heat transfer (Q) = m.Cp.( T₂- T₁) J</em>

                                            = 0.185 × 2.108 × (283 - 473)

                                        <em>  Q = -74.09 KJ</em>

<em>Heat rejected from ice is 74 J</em>


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You throw a rock straight up and find that it returns to your hand 3.40 s after it left your hand. Neglect air resistance. What
Soloha48 [4]

Answer:

The maximum height of the rock is 14.2 m

Explanation:

The equations that describe the height and velocity of the rock are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the object at time t

y0 = initial height

t = time

g = acceleration due to gravity (-9.8 m/s² if upward is positive)

v = velocity of the object at time t

We know that at t = 3.40 s, the rock is in your hand again. Then, if we place the origin of the frame of reference at your hand, the position of the rock at 3.40 s is 0 m. Using the equation of the position, we can calculate the initial velocity that we will need to obtain the max-height.

y = y0 + v0 · t + 1/2 · g · t²

0 = v0 · 3.40 s - 1/2 · 9.8 m/s² · (3.40 s)²

(1/2 · 9.8 m/s² · (3.40 s)² ) / 3.40 s = v0

v0 = 16.7 m/s

At max-height, the velocity of the rock is 0. Then, using the equation of velocity we can calculate the time it takes the rock to reach the max-height. With that time, we can calculate the maximum height.

v = v0 + g · t      (at max-height, v = 0)

0 = 16.7 m/s - 9.8 m/s² · t

- 16.7 m/s /  - 9.8 m/s² = t

t = 1.70 s

Now, using this time in the equation of height:

y = y0 + v0 · t + 1/2 · g · t²

y = 0 m + 16.7 m/s · 1.70 s - 1/2 · 9.8 m/s² · (1.70 s)²

y = 14.2 m

The maximum height of the rock is 14.2 m

8 0
3 years ago
You have a neutral balloon. What is its charge after 12000 electrons have been removed from it? The elemental charge is 1.6 × 10
AleksandrR [38]

Answer:

1.92×10^-9 microCoulomb

Explanation:

Elemental charge = 1.6×10^-19 Coulomb

Charge of balloon after 12,000 electrons have been removed from it = 12,000 × 1.6×10^-19 Coulomb = 1.92×10^-15 Coulomb = 1.92×10^-15/10^-6 = 1.92×10^-9 microCoulomb

6 0
3 years ago
Which of the following is best described as a synthesis reaction? (2 points) 2HgO → 2Hg + O2 AgNO3 + NaCl → AgCl + NaNO3 HCl + N
Shtirlitz [24]

2Na + Cl₂ → 2NaCl

Explanation:

The reaction of sodium metal with chlorine gas to produce sodium chloride is a typical example of synthesis reaction.

Combination or synthesis involves the formation of a single product from two or more reactants.

    A + B ⇒ C

  In this kind of chemical reaction, a single product is formed or some compounds by the union of elements is notable.

The driving force for this category of chemical reaction is the large and negative heat of formation of the product.

learn more:

Chemical reaction brainly.com/question/3953793

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
You move a 25 n object 4 meters. find the work you did
d1i1m1o1n [39]
In physics, "work<span>" is when a force applied to an object moves the object in the same direction as the force. If someone pushes against a wall, no </span>work<span> is done on the system. It is calculated as follows:

Work = Force x distance
Work = 25 N x 4 meters
Work = 100 N.m</span>
5 0
3 years ago
Read 2 more answers
you have been called to testify as a as an expert witness in a trial involving a head-on collision Car A weighs 1515 pounds and
GrogVix [38]

Answer:

70.6 mph

Explanation:

Car A mass= 1515 lb

Car B mass=1125 lb  

Speed of car B is 46 miles/h

Distance before locking, d=19.5 ft

Coefficient of kinetic friction is 0.75

Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

Momentum_B=1125*67.4666668 ft/s

Initial momentum of car A is given by

Momentum_A=1515v_a where v_a is velocity of A

Taking East as positive and west as negative then the sum of initial momentum is

1515v_a-(1125*67.4666668 ft/s)

The common velocity is represented as v_c hence after collision, the final momentum is

Momentum_final=(m_a+m_b)v_c=(1515+1125)v_c=2640v_c

From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence

1515v_a-(1125*67.4666668 ft/s)= 2640v_c

The acceleration of two cars a=-\mug=-0.75*32.17=-24.1275 ft/s^{2}

From kinematic equation

v^{2}=u^{2}+2as hence

v^{2}-u^{2}=2as

0^{2}-(v_c)^{2}=2*-24.1275*19.5

v_c=\sqrt{2*24.1275*19.5}=30.67 ft/s

Substituting the value of v_c in equation 1515v_a-(1125*67.4666668 ft/s)= 2640v_c

1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

1515v_a=(1125*67.4666668 ft/s)+2640*30.67

v_a=\frac {156868.8}{1515}=103.5438 ft/s

\frac {103.5438}{1.46667}=70.59787 mph\approx 70.60 mph

3 0
3 years ago
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