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3 years ago

How much he is given out 185 g of lead cools from 200 Celsius to 10 Celsius

Physics

1 answer:

ioda3 years ago

5 0

Given data

mass (m) = 185 g = 0.185 Kg ,

temperature (T₁) = 200°C = 200 + 273 = 473 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k

Heat transfer (Q) = m.Cp.( T₂- T₁) J

= 0.185 × 2.108 × (283 - 473)

Q = -74.09 KJ

Heat rejected from ice is 74 J

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Answer:

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Answer:

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Since Robert Millikan determined the charge of a single electron is

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Let's test the possible charges listed in the question:

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$-3.2 \times 10 ^{-19 }$ . Since 3.2 is an exact multiple of 1.6, this is also a possible charge of the oil droplets

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$-5.6 \times 10 ^{-19 },\ -9.4 \times 10 ^{-19 }$ cannot be a possible charge for an oil droplet because they are not exact multiples of 1.6

Finally, the charge $-4.8 \times 10 ^{-19 }\ C$ is four times the charge of the electron, so it is a possible value for the charge of an oil droplet

Summarizing, the following are the possible values for the charge of an oil droplet:

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