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s2008m [1.1K]
3 years ago
13

Ohms law is A.(R=E/W). B.(R=E/1). C.(E/Z). D.none of them

Physics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

D. none of them.

Explanation:

This is because Ohm's law is:

Voltage = Current × Resistance

or,

V = IR

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What are cells? what is the relationship between cells and organisms?​
Leona [35]

Answer:

cells are the things that u are made of

Explanation:

the relationship between cells and organisms is that cells make up organisms and without cells we would not  be here

<h2><u><em>hope this helps plz mark as brainliest</em></u></h2>
7 0
3 years ago
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To collect quantitative data, scientists use all of the following except _____.
Leto [7]
You would use all of the following except for 3. descriptive categories because, that is a qualitative observation using descriptions and not a quantitative observation using numbers.<span />
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3 years ago
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Find the first three harmonics of a string of linear mass density 2. 00 g/m and length 0. 600 m when the tension in it is 50. 0
gavmur [86]

The first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

<h3>Velocity of the wave</h3>

The velocity of the wave is calculated as follows;

v = √T/μ

where;

  • T is tension
  • μ is mass per unit length = 2 g/m = 0.002 kg/m

v = √(50/0.002)

v = 158.1 m/s

<h3>First harmonic or fundamental frequency of the wave</h3>

f₀ = v/λ

where;

  • λ is the wavelength = 2L

f₀ = v/2L

f₀ = 158.1/(2 x 0.6)

f₀ = 131.8 Hz

<h3>Second harmonic of the wave</h3>

f₁ = 2f₀

f₁ = 2(131.8 Hz)

f₁ = 263.6 Hz

<h3>Third harmonic of the wave</h3>

f₂ = 3f₀

f₂ = 3(131.8 Hz)

f₂ = 395.4 Hz

Thus, the first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

Learn more about harmonics here: brainly.com/question/4290297

#SPJ1

6 0
1 year ago
A player kicks a football from ground level with an initial velocity of 27.0 m/s, 30.0° above the
Gelneren [198K]

Answer:

Option B. 2.8 s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 27 m/s

Angle of projection (θ) = 30

Acceleration due to gravity (g) = 9.8 m/s²

Time of flight (T) =?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = 2 × 27 × Sine 30 / 9.8

T = 2 × 27 × 0.5 / 9.8

T = 27 / 9.8

T = 2.8 s

Therefore, time of flight of the ball is 2.8 s

7 0
3 years ago
Suddenly a worker picks up the bag of gravel. Use energy conservation to find the speed of the bucket after it has descended 2.3
fiasKO [112]

Explanation:

A worker picks up the bag of gravel. We need to find the speed of the bucket after it has descended 2.30 m from rest. It is case of conservation of energy. So,

\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh}

h = 2.3 m

v=\sqrt{2\times 9.8\times 2.3} \\\\v=6.71\ m/s

So, the speed of the bucket after it has descended 2.30 m from rest is 6.71 m/s.

8 0
3 years ago
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