Question

How many moles are contained in 3.131 × 1024 particles?

Answer 1

Answer:

There are 5.199 moles in $3.131\times 10^{24}$ particles.

Explanation:

$N=n\times N_A$

Where:

N = Number of particles / atoms/ molecules

n = Number of moles

$N_A=6.022\times 10^{23} mol^{-1}$ = Avogadro's number

We have:

N = $3.131\times 10^{24}$

n =?

$n=\frac{N}{N_A}=\frac{3.131\times 10^{24}}{6.022\times 10^{23} mol^{-1}}$

n = 5.199 moles

There are 5.199 moles in $3.131\times 10^{24}$ particles.