The first two pairs.. just substitute the x-coordinate and find y
G is the right answer I just did it no cap
1)
45x^3+5x
the GCF is 5x because that is a factor of both.
The answer would be 5x(9x^2+1)
2)
u^2-5u+6
factoring is finding what multiplies to the last number to add to the middle number. Those numbers are -3 and -2.
the answer would be (u-3)(u+2)
3)
m^2-49
difference of perfect squares
answer is (m+7)(m-7)
4)
x^5+4x^4+3x^3
GCF is x^3 so it's x^3(x^2+4x+3)
Factor that and it's x^3(x+3)(x+1)
Answer:
32.5 units²
Step-by-step explanation:
We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.
First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.
5 · 5 = 25 units²
Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.
8 - 5 = 3
So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.
5 · 3 = 15
= 7.5
The area of the triangle is 7.5 units².
Finally, we can add the area of the triangle and the square together.
25 + 7.5 = 32.5
The area of the figure, then, is 32.5 units².
The answer is the last option.
I hope this helps ^^