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andrew11 [14]
2 years ago
14

You are asked to tutor a friend in algebra with adding and subtracting trinomials. Create an example of how to add two trinomial

s and how to subtract two trinomials. Come up with two trinomials and be sure to
Mathematics
1 answer:
vesna_86 [32]2 years ago
4 0
Addign trinomials (2x+4xy+8z)+(8x+5xy+23z) all you have to do is combine the like terms 2x and 8x= 10x, 4xy+5xy=9xy, and 8z+23z=31z. so the simplified answer to adding the trinomials would be 10x+9xy+31z. 

Subtacting trinomials (4x+9y+3) - (-1+3x-2y) . 
When doing subtracting you still combine like terms but this time you change the sign before every term. If that is confusing, just pretend there is a negative 1 infront of parenthases and multiply that before you subtracts the two trinomials. so...
4x - 3x= x, 9y+2y=11y and 3+1=4. so simplified answer of the subtraction would be x+11y+4 

I hope this helped :) Good luck !

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Makovka662 [10]
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6 0
3 years ago
Helppp I really need this question answered
Ne4ueva [31]

Answer:

32.5 units²

Step-by-step explanation:

We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.

First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.

5 · 5 = 25 units²

Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.

8 - 5 = 3

So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.

5 · 3 = 15

\frac{15}{2} = 7.5

The area of the triangle is 7.5 units².

Finally, we can add the area of the triangle and the square together.

25 + 7.5 = 32.5

The area of the figure, then, is 32.5 units².

The answer is the last option.

I hope this helps ^^

6 0
2 years ago
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