Question

A 0.150 kg metallic block measures 25.0 mm in length, 43.0 mm in width, and 19 .0 mm in height. what is the density of the metallic block in g/cm3?

Answer 1

Answer:

7.35 g/cm^3

Explanation:

The mass of the block is:

$m=0.150 kg=150 g$

While the sizes of the block are:

$L_1 = 25.0 mm = 2.5 cm\\L_2 = 43.0 mm = 4.3 cm\\L_3 = 19.0 mm=1.9 cm$

So the volume is

$V=2.5 cm \cdot 4.3 cm \cdot 1.9 cm =20.425 cm^3$

And now we can find the density by dividing the mass of the block by its volume:

$d=\frac{m}{V}=\frac{150 g}{20.425 cm^3}=7.35 g/cm^3$

Answer 2

Density = (mass) / (volume)

Mass = 0.150 kg = 150 grams

Volume = (length) · (width) · (height)

Volume = (2.5 cm) · (4.3 cm) · (1.98 cm)

Volume = 21.285 cm³

Density =  (150 g) / (21.285 cm³)

Density =  7.05 g/cm³