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emmainna [20.7K]
4 years ago
10

cIn a traction drive, a 1.4-in.-diameter cylindrical roller is preloaded against a 3.4-in. diameter cylindrical roller. The stee

l rollers are 3.7 in. wide and the preload force is 56 lb. The axes of the cylinders are parallel. Calculate the maximum contact pressure in ksi.
Engineering
1 answer:
Kaylis [27]4 years ago
4 0

Answer:

The maximum contact pressure is 12.658 ksi

Explanation:

The contact modulus is:

Δ = M

M=2*(\frac{1-v^{2} }{E} )=2*(\frac{1-0.3^{2} }{30x10^{6} } )=6.06x10^{-8} in^{2} /lb

The radius of curvature is:

r1 = D1/2 = 1.4/2 = 0.7 in

r2 = D2/2 = 3.4/2 = 1.7 in

The maximum contact pressure is:

P=0.564\sqrt{\frac{F*(\frac{1}{r_{1} }+\frac{1}{r_{2} })  }{L*M} } =0.564\sqrt{\frac{56*(\frac{1}{0.7}+\frac{1}{1.7})  }{3.7*6.06x10^{-8} } } =12658.09psi=12.658ksi

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Answer:

Goal address: Based on the above Ethernet outline design, we get that the goal address begins from the first hex worth and is of size 12 hex values (got from question 1). In light of the bundle given, we get that the goal address is 6c40 0889 c448.  

Source address: Similarly, the source address begins after the goal address and is of size 12 hex values (got from question 1). Thus, the appropriate response is f832 e4a7 fb38.  

Type/Length: The sort/length begins after the source address and is of size 4 hex values (got from question 1). Thus, the appropriate response is 0806.  

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The Ethernet parcel type characterizes the convention utilized for sending the bundle information. We realize that type 0x0800 demonstrates the IPv4 convention, 0x0806 shows an ARP convention, and 0x86DD demonstrates an IPv6 convention. In light of the appropriate response we got in Question 3, we realize that the sort/length esteem for the given parcel is 0806, which implies that convention utilized for sending the information bundle was ARP convention.

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3 years ago
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algol13

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Force(P) = pressure × area

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