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emmainna [20.7K]
4 years ago
10

cIn a traction drive, a 1.4-in.-diameter cylindrical roller is preloaded against a 3.4-in. diameter cylindrical roller. The stee

l rollers are 3.7 in. wide and the preload force is 56 lb. The axes of the cylinders are parallel. Calculate the maximum contact pressure in ksi.
Engineering
1 answer:
Kaylis [27]4 years ago
4 0

Answer:

The maximum contact pressure is 12.658 ksi

Explanation:

The contact modulus is:

Δ = M

M=2*(\frac{1-v^{2} }{E} )=2*(\frac{1-0.3^{2} }{30x10^{6} } )=6.06x10^{-8} in^{2} /lb

The radius of curvature is:

r1 = D1/2 = 1.4/2 = 0.7 in

r2 = D2/2 = 3.4/2 = 1.7 in

The maximum contact pressure is:

P=0.564\sqrt{\frac{F*(\frac{1}{r_{1} }+\frac{1}{r_{2} })  }{L*M} } =0.564\sqrt{\frac{56*(\frac{1}{0.7}+\frac{1}{1.7})  }{3.7*6.06x10^{-8} } } =12658.09psi=12.658ksi

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