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kondaur [170]
4 years ago
11

An insulated rigid tank is divided into two compartments of different volumes. Initially, each compartment contains the same ide

al gas at identical pressure but at different temperatures and masses. The wall separating the two compartments is removed and the two gases are allowed to mix. Assuming constant specific heats, find the simplest expression for the mixture temperature written in the form
T3 = f(m1m2, m2m3, T1, T2)T 3=f( m 2m 1, m 3m 2,T 1,T 2) where m3m 3and T3T 3are the mass and temperature of the final mixture, respectively.
Engineering
1 answer:
storchak [24]4 years ago
8 0

Answer:

Explanation:

Given that

Mass of 1 = m_1

Mass of 2 = m_2

Temperature in  1 = T_1

Temperature in 2 = T_2

Pressure remains i  the group apartment

The closed system and energy balance is

E_{in}-E_{out}=\Delta E_{system}

The kinetic energy and potential energy are negligible

since it is insulated tank ,there wont be eat transfer from the system

And there is no work involved

\Delta U = 0

Let the final temperature be final temperature

m_1+c_v(T_3-T_1)+m_2c_v(T_3+T_2)=0\\\\m_1+c_v(T_3-T_1)=m_2c_v(T_2-T_3)---(i)

Using mass balance

m_3+m_2+m_1

from eqn i

m_1+c_v(T_3-T_1)=m_2c_v(T_2-T_3)m_1T_3-m_1T_1=m_2T_2-m_2T_3\\\\m_1T_3+m_2T_3=m_2T_2+m_1T_1\\\\(m_1+m_2)T_3=m_1T_1+m_2T_2\\\\(m_1)T_3=m_1T_1+m_2T_2\\\\T_3=\frac{m_1T_1_m_2T_2}{m_3}

Therefore the final temperature can be express as

\large \boxed {T_3=\frac{m_1}{m_3} T_1+\frac{m_2}{m_3}T_2 }

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Answer:

the percent increase in the velocity of air is 25.65%

Explanation:

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3 years ago
A 4-lb ball B is traveling around in a circle of radius r1 = 3 ft with a speed (vB)1 = 6 ft>s. If the attached cord is pulled
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Answer:

r₂ = 1.5 ft

t = 0.75 s

Explanation:

W = 4 lb    ⇒  m = W/g = 4 lb / 32.2 ft/s² = 0.12 slug

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Conserving angular momentum we have:

m*v₁*r₁ = m*v₂*r₂    ⇒     r₂ = v₁*r₁ / v₂

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Answer:

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Explanation:

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Answer:

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5. draw the pV diagram using the 300F isothermal line

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