Answer: The rate of disappearance ( -Δ[B]/Δt) under the same conditions is 0.200 M/s.
Explanation:
Initial Rate of the reaction = 0.100 M/s
Rate of disappearance of B:
![-\frac{1}{2}\frac{\Delta [B]}{\Delta t}=0.100 M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5CDelta%20%5BB%5D%7D%7B%5CDelta%20t%7D%3D0.100%20M%2Fs)
![-\frac{\Delta [B]}{\Delta t}=2\times 0.100 M/s=0.200 M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B%5CDelta%20%5BB%5D%7D%7B%5CDelta%20t%7D%3D2%5Ctimes%200.100%20M%2Fs%3D0.200%20M%2Fs)
The rate of disappearance ( -Δ[B]/Δt) under the same conditions is 0.200 M/s.
Answer:
May be boiling is the answer because all other options are a proper chemical changes.
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
<span>Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.
Following is the reaction involved in above process:
</span>
+
→
→
+
+ 3
<span> + 177 MeV
</span>
Here,
= Fission material,
= projectile,
= intermediate nuclei,
and
= Fission product
Equation is as follow,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Oxidation:
3 CO → 3 CO₂
Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,
3 CO → 3 CO₂ + 6 e⁻
Reduction:
Fe₂O₃ → 2 Fe
Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,
Fe₂O₃ + 6e⁻ → 2 Fe
Result:
Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.
