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3 years ago

Who discovered the proton? Crookes Rutherford Balten Chadwick

Chemistry

1 answer:

Ronch [10]3 years ago

5 0

Answer:

Sir James Chadwick discovered proton

Explanation:

Sir James Chadwick, was a British physicist who was awarded the 1935 Nobel Prize in Physics for his discovery of the neutron in 1932. In 1941, he wrote the final draft of the MAUD Report, which inspired the U.S. government to begin serious atomic bomb research efforts.

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Question: why do astronauts wear organge suits vs white suits<br><br> Full answer please..

Alexeev081 [22]

Astronauts are found wearing orange-colored Advanced Crew Escape Suit (ACES) while the space shuttle is ascending or entering into space. This peculiar shade of orange known as “International Orange” was chosen for safety as it is highly visible against any kind of landscape, especially in the sea.

7 0

3 years ago

Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. The melting point of

lubasha [3.4K]

Cool liquid from 314 K to 273 K, freeze liquid at 273 K, and cool solid to 263 K.

5 0

3 years ago

Read 2 more answers

Solve and round to the correct number of significant figures: 129 ÷ 29.20

Scilla [17]

4.42

Because when you divide 129/29.20, you get a long string of numbers. 4.417808219178082...

So you round to the significant figure which in this case is 2 decimal places because 29.20 has 2 decimal places.

PS did you draw that car? Cuz im into drawing cars too.

5 0

3 years ago

The vaporization of 1 mole of liquid water (system) at 100.9 C, 1.00 atm, is endothermic.

yan [13]

Answer:

a) The work done is 10.0777 kJ

b) The water's change in internal energy is -122.1973 kJ

Explanation:

Given data:

1 mol of liquid water

T₁ = temperature = 100.9°C

P = pressure = 1 atm

Endothermic reaction

T₂ = temperature = 100°C

1 mol of water vapor

VL = volume of liquid water = 18.8 mL = 0.0188 L

VG = volume of water vapor = 30.62 L

3.25 moles of liquid water vaporizes

Q = heat added to the system = -40.7 kJ

Questions: a) Calculate the work done on or by the system, W = ?

b) Calculate the water's change in internal energy, ΔU = ?

Heat for 3.25 moles:

$Q_{1} =3.25*(-40.7)=-132.275kJ$

The work done:

$W=-nP*delta(V)=-3.25*101.33*(0.0188-30.62)=10077.6637J=10.0777kJ$

The change in internal energy:

$delt(U)=W+Q_{1} =10.0777-132.275=-122.1973kJ$

7 0

3 years ago

Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o

Viefleur [7K]

Answer:

$P_2=404 kPa$

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

$P_1V_1=P_2V_2$

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

$V_2=\frac{1}{4} V_1$

We can compute the new pressure:

$P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa$

Which means the pressure is increased by a factor of four.

Regards.

7 0

3 years ago