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yaroslaw [1]
3 years ago
9

Convert 0.74Kcal/min to cal/sec

Chemistry
1 answer:
professor190 [17]3 years ago
6 0
<span>0.74 Kcal/min x 1000 cal/60 s         


</span>
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What is the correct name of this compound?
Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

8 0
3 years ago
What is the difference between parent material
Kazeer [188]

Answer:

Parent material is the geologic material from which soil horizons form. Many soils have more than one parent material, for example loess over till. ... Every soil horizon has a parent material, but the same parent material usually appears different in different horizons because soil formation processes have altered it.

Explanation:

8 0
3 years ago
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
How many electrons may be accommodated in the first three energy levels?
viktelen [127]
Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. Some points will be nice
3 0
2 years ago
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A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis
Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa

The factor will the volume of the diver's lungs change upon arrival at the surface:

\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4

5 0
3 years ago
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