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3 years ago

Convert 0.74Kcal/min to cal/sec

Chemistry

1 answer:

professor190 [17]3 years ago

6 0

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Which of the following explains how electricity flows? Protons flow from the positive end of a source towards the negative end.E

zalisa [80]

I know for a fact the answer would (not) be the last option. This would not be a way that electricity would be able to really flow.

Your correct answer would be of when the "e<span>lectrons flow from the negative end of a source towards the positive end."

This would be because when the electrons would be free, they would have enough energy to then move from the negative side of the end, to the positive side.</span>

7 0

3 years ago

2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) (balanced)

Triss [41]

Answer:

Percent yield = 65.2 %

Explanation:

The reaction determines this:

2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.

We determine the moles of chlorine:

52 g . 1mol /70.9g = 0.733 moles of Cl₂

3 moles of gas can produce 2 moles of salt

Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃

We convert moles to mass to predict the 100 % yield

0.489 mol . 133.3 g /mol = 65.19 g

Percent yield = (Yield produced / 100 % yield) . 100

Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %

3 0

3 years ago

A strong electrolyte is one that __________ completely in solution

hodyreva [135]

That would be 'ionises' .

4 0

4 years ago

What amount of oxygen gas in moles contains 1.8x10^22 molecules?

exis [7]

Answer:

<h2>0.03 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

$n = \frac{1.8 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.02990...$

We have the final answer as

<h3>0.03 moles </h3>

Hope this helps you

7 0

3 years ago

In a constant‑pressure calorimeter, 70.0 mL of 0.310 M Ba ( OH ) 2 was added to 70.0 mL of 0.620 M HCl . The reaction caused the

Leno4ka [110]

Explanation:

Below are attachments containing the solution

5 0

3 years ago