Atoms are arranged in molecular compounds in groups.

For covalent compounds: 
consider drawing the lewis structure of the covalent compound in question, putting the atom which is least electronegative (save hydrogen) in the center.

4 0

2 years ago

Using the potential given below, calculate the activity of cl^- in 1M KCl solution.

MissTica

Answer:

Explanation:

E° (calomel electrode) = 0.268 v

E( calomel electrode, 1M KCl) = 0.280 v

For calomel electrode

$E = E^0 _( Hg^+/Hg ) - \frac{.059}{2} \times log( a_{cl^-} )^2$

$.280 = .268 - \frac{.059}{2} \times log( a_{cl^-} )^2$

$.012= - \frac{.059}{2} \times log( a_{cl^-} )^2$

$log( a_{cl^-})^2= - .4067$

$a_{cl^-_}$ = 0.626 .

3 0

2 years ago

What is a chemical equation that shows the same number of each kind of atom on both sides of the equation called?

dem82 [27]

Answer:

balanced

Explanation:

shows the same number of each kind of atom on both sides

7 0

3 years ago

Read 2 more answers

One way to remove nitrogen oxide from smokestack emissions is to react it with ammonia: 4 NH3 (g) + 6 NO (g) ----------> 5 N2

Rama09 [41]

The answer 12,3 mol of NO reacts with 8.2_mol of ammonia 5.87 mol of NO yields 4.89_ mol nitrogen Proof This kind of question is called mole-mole problem, for solving it we process as follow 4 NH3 (g) + 6 NO (g) ----> 5 N2 (g) + 6H2O 4moles 6moles X ---------------12.3 moles This implies x=12.3 x 4 /6=8.2 moles, so 12.3 moles of nitrogen corresponds to 8.2 ammoniac 4 NH3 (g) + 6 NO (g) ---> 5 N2 (g) + 6H2O 6 moles 5moles . 5.87 moles---- x=? After cross-multiplication, 5.87 x 5 / 6 = 4.89, so 5.87 moles of nitrogen oxyde yelds 4.89 moles of nitrogen

7 0

3 years ago