"A sample of air at 7.50 atm is cooled from 448K to 224K. If the volume remains constant, what is the final pressure?
2 answers:
Answer:
P/T = constant (T = absolute temperature)
P1 = 7.5 atm
T1 = 224 K
P2 = ?
T2 = 448 K
P1/T1 = P2/T2
P2 = (T2/T1)*P1 = (448/224)*(7.5 atm) = 15.00 atm
Explanation:
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Answer:
Explanation:
Applying gas law formulae:
P1/T1 = P2/T2
Where P1 = initial pressure (atm) = 7.5
T1 = initial temperature in Kelvin(K) = 448
P2 = final pressure (atm) = unknown
T2 = final temperature in Kelvin(K) = 224
From the above Formula make P2 the subject of formula
P2 = P1T2/T1
P2 = 7.50*224/448
P2 = 1680/448
P2 = 3.75ATM
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