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babunello [35]
4 years ago
10

Which function do cheetahs serve in temperate grassland?

Chemistry
2 answers:
Nina [5.8K]4 years ago
5 0
This answer would be primary consumers
Keith_Richards [23]4 years ago
5 0

the answer would be C.

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Plz help
Marizza181 [45]

Answer: I dont want to make you wrong but I think its D.

7 0
3 years ago
An element X that has 15 protons and 15 electrons, loses three
Wewaii [24]

Answer:

+3

12 electrons and 15 protons.

Explanation:

The element having 15 electrons and 15 protons have atomic number 15. We know that when an atom lose or gain the electron ions are formed.

Anion formation:

Anion is formed when electron is accept by an atom.

X + e⁻ → X⁻

Cation formation:

Cation is formed when electron lose be an atom.

X → X⁺ + e⁻

The given atom loses 3 electrons thus oxidation number will be +3 and cation is formed.

X → X³⁺ + 3e⁻

Now element X have 15 protons and 12 electrons.

8 0
3 years ago
How would the calculated value of Ksp be affected by the accidental and unknowing collection of solid lead(II) chloride via pipe
Papessa [141]

Explanation:

It is known that relation between Gibb's free energy and equilibrium or reaction quotient is as follows.

             \Delta G = \Delta G^{o} + 2.303 RT logQ    ..... (1)

At equilibrium, \Delta G = 0. Also, Q = K this means that reaction is at equilibrium.

Therefore, formula in equation (1) will become as follows.

                \Delta G^{o} = -2.303 RT log K      ....... (2)

It is known that for a sparingly soluble salt, K = K_{sp}

Thus, equation (2) will become as follows.

                \Delta G^{o} = -2.303 RT log K_{sp}  ....... (3)

So, when value of K_{sp} increases then there will be decrease in the value of \Delta G^{o} according to equation (3).

Hence, we can conclude that the calculated value of K_sp would be too big.

5 0
4 years ago
Which observations would have been consistent with Marie Curie's work? Check all that apply.
Ne4ueva [31]

Answer:2,3,4

Explanation:

6 0
3 years ago
The vapor pressure of pure water at 250C is 23.77 torr. What is the vapor pressure of water above a solution that is 1.500 m glu
Olegator [25]

Answer:

Vapor pressure of water = 23.14torr

Explanation:

When you made a solution, vapor pressure decreases following Raoult's law:

P_{solution} = X_{solvent} P_{solvent}

<em>Where P is vapor pressure and X mole fraction</em>

As vapor pressure of water is 23.77torr we must find the mole fraction of water knowing the solution is 1.500m glucose (That is 1.500 moles of glucose per kg of water = 1000g of water).

1000g of H₂O are, in moles (Molar mass: 18.02g/mol):

1000g H₂O ₓ (1mole / 18.02g) = 55.5 moles of H₂O.

As we know now the solution contains 55.5 moles of water and 1.5 moles of glucose. Thus, mole fraction of water (Solvent) is:

X_{H_2O} = \frac{55.5molesH_2O}{55.5molesH_2O + 1.5 molesGlucose} = 0.9737

Replacing in Raoult's law, pressure of water above the solution is:

P_{solution} = X_{solvent} P_{solvent}

P_{solution} = 0.9737*23.77torr

<h3>Vapor pressure of water = 23.14torr</h3>
7 0
4 years ago
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