Answer:
Electro negativity decreases down the group
Explanation:
One of the known periodic trends is that electro negativity decreases down the group but increases across the period. The electro negativity of fluorine is 3.98 on the Pauling's scale while that of bromine is 2.96. Hence the magnitude of charge separation and degree of partial positive charge on hydrogen in HF must be much greater than that of HBr to a large extent due to the significant difference in electronegativity in HF compared to HBr.
Preparation of small volumes of gases.
Answer:
a) rate law = k[HgCl₂][C₂O₄²⁻]²
b) K = 8.67 * 10⁻⁵M⁻²s⁻¹
c) rate = 2.55 * 10⁻⁵Ms⁻¹
Explanation:
a) From the given data, rate law is given as: rate = k[HgCl₂]ᵃ[C₂O₄²⁻]ᵇ
Note: Further calculations and explanations are found in the attachment below
Answer:
The combustion reaction is the last one, with the C4H12 compound.
Remember that all the combustion reactions has the oxygen as a substract and for products, you'll have CO2 and water.
Explanation:
Explanation:
both iron and sulphur in FeS2 undergo a change in oxidation state.
O2° -->2O degree2- Total decrease = 2×2=4
So, 4FeS2+11O2 --> 2Fe2O3+8 SO2
Hence, balanced