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3 years ago

Find the number of moles of water that can be formed if you have 182 mol of hydrogen gas and 86 mol of oxygen gas.

1 answer:

3 0

Water has a chemical formula of H2O. This means that for every 2 moles of hydrogen and 1 mole of oxygen, one mole of water will be formed.

Note that hydrogen gas and oxygen gas are both biatomic molecules.

(1) (182 mol H2) x (1 mol H2O/ 1 mol H2) = 182 mol H2O
(2) (86 mol O2) x (2 mol H2O / 1 mol O2) = 172 mol H2O

We choose the smaller number of the two as the answer to this item. Thus, the answer to this question is 172 mol of H2O can be formed out of the given quantities.

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Heat left over from when the earth was formed about 4.6 billion years ago is one source of INTERNAL energy. What is the other so

siniylev [52]

Answer:

the gravity

Explanation:

i hope you help this answer

4 0

2 years ago

Read 2 more answers

Which energy source from a reservoir would provide affordable, abundant electricity for a factory? solar panels wind turbines ga

Sunny_sXe [5.5K]

The energy source from a reservoir would provide affordable, abundant electricity for a factory is a hydroelectric power plant; option D.

<h3>What is energy?</h3>

Energy is the ability to do work.

Energy generating plants may either use wind, water or solar energy to produce electrical energy.

The most abundant source of energy from a reservoir is hydroelectric power plant.

Therefore, the energy source from a reservoir would provide affordable, abundant electricity for a factory is a hydroelectric power plant.

In conclusion, hydroelectric power plants are reservoirs of abundant energy supply.

Learn more about hydroelectric power plants at: brainly.com/question/3406557

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7 0

2 years ago

U-235 undergoes many different fission reactions. For one such reaction, when U-235 is struck with a neutron, Ce-144 and Sr-90 a

Lostsunrise [7]

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is $^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + x^{1}_{0}n + y^{0}_{-1}\beta$

Now, we balance the mass on both reactant and product side as follows.

235 + 1 = $144 + 90 + (x \times 1) + (y \times 0)$

236 = 234 + x

x = 236 -234

= 2

So, now we balance the charge on both reactant and product side as follows.

92 + 0 = $58 + 38 + (x \times 0) + (y \times -1)$

92 = 96 - y

y = 4

Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.

Therefore, reaction equation will be as follows.

$^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + 2^{1}_{0}n + 4^{0}_{-1}\beta$

8 0

3 years ago

A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At

Mazyrski [523]

According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

P</span>₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm

T₁ = 35 °C + 273 = 308 K

P₂ = ?

T₂ = 0 °C + 273 = 273 K

Solving Eq. 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K

P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.

5 0

3 years ago

What volume of lead (of density 11.3 g/cm3) has the same mass as 330 cm3 of a piece of redwood (of density 0.38 g/cm3)?

zimovet [89]

Answer:

The sample of lead has a volume of 11.1 cm³

Explanation:

<u>Step 1:</u> Data given

x cm³ lead has a density of 11.3 g/cm³

it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³

<u>Step 2</u>: Calculate mass of the piece of redwood

Density = mass/volume

mass = density * volume

Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams

Since the sample of lead has the same mass, it also has a mass of 125.4 grams

<u>Step 3</u>: Calculate volume of the lead

Density = mass/ volume

Volume = mass/ density

Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³

The sample of lead has a volume of 11.1 cm³

3 0

3 years ago