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3 years ago

9

Balance NH3 + H2O2 → __ NH4O

1 answer:

lord [1]3 years ago

6 0

2NH3 + H2O2 → N2H4 + 2H2O

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10 ejemplos de disoluciones identificando el soluto y el solvente y el tipo de disolucion que corresponde

Keith_Richards [23]

Answer:

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3 years ago

How does the concentration of reactants affect the rate <br>of Chemical reaction? explain in short

Neporo4naja [7]

Higher concentration of reactants equals faster rate of reaction. Reactions occur when particles collide effectively, and by increasing the concentration of reactants, you increase the number of effective collisions, thereby making the reaction occur faster.

6 0

3 years ago

Read 2 more answers

a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what

jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in liters.

$n$ - Molar quantity, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

$\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}}$ (2)

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$V_{1}$ , $V_{2}$ - Initial and final volume, measured in liters.

$T_{1}$ , $T_{2}$ - Initial and final temperature, measured in Kelvin.

If we know that $P_{1} = 121\,kPa$ , $P_{2} = 202\,kPa$ , $V_{1} = 2.7\,L$ , $T_{1} = 288\,K$ and $T_{2} = 303\,K$ , the final volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}$

$V_{2} = 1.702\,L$

The gas will occupy a volume of 1.702 liters.

6 0

3 years ago

What is the correct answer please

Anestetic [448]

Answer:

I think it's the second answer --If you increase the acidity..

I hope answer I can answer your question!

7 0

3 years ago

A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine

Angelina_Jolie [31]

The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

molar mass=33.29g

<h3>What mass of krypton tetrachloride can be produced assuming 100% yield?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Therefore

n=(0.50)(15.)/0.082*623

n=0.147mol

Hence for clorine

n=0.441mol

Given the reaction

Kr+2cl2---->KrCL4

Hence

molar mass=225.60*0.147

molar mass=33.29g

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4 0

2 years ago