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Kipish [7]
2 years ago
9

Balance __ NH3 + __ H2O2 → __ NH4O

Chemistry
1 answer:
lord [1]2 years ago
6 0
2NH3 + H2O2 → N2H4 + 2H2O
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Which of the following is a common property of both strong acid and strong base?
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Answer:please can you help me with the last question that I asked I will help you if you help me please help

Explanation:

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In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
2 years ago
The molecular formula of butane is C4H10. It is obtained from petroleum and is used commonly in LPG (Liquefied Petroleum Gas) cy
LUCKY_DIMON [66]

Answer:

Explanation:

Butane is an alkane and has no multiple bond in it.

The isomers of butane are

a) n-butane

b) t-butane

The structures are shown in the figure.

The most stable radical will be tertiary butyl radical.

The structures are shown in figure.

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<h3><u>Answer</u>;</h3>

= 226 Liters of oxygen

<h3><u>Explanation</u>;</h3>

We use the equation;

LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;

Moles of  LiClO4;

(500 g LiClO4) / (106.3916 g LiClO4/mol)

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= 9.3992 moles of Oxygen

V = nRT / P

= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)

= 226 L of oxygen

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3 years ago
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